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##' Get Unique Pairs
##'
##' For the pairwise SNHT, many difference time-series must be computed.
##' However, if location i is used for location j, then it's very likely that
##' location j will be used for location i. Thus, the pairs object will likely
##' have many duplicate pairs. To save computation time, this function finds
##' which pairs are unique.
##'
##' @param pairs The pairs list object, as returned by ?getPairs.
##'
##' @return data.frame with columns loc1 and loc2. This data.frame will have
##' no duplicates, and describes all the pairs that need to be computed.
##'
getUniquePairs = function(pairs){
#Compute all pairs that will need to be analyzed:
uniquePairs = data.frame(loc1 = rep(names(pairs), lapply(pairs,length))
,loc2 = do.call("c", pairs), stringsAsFactors=F )
#Remove non-unique pairs. Start at nrow(pairsDf) and work down. Otherwise, the
#iterator would break when you delete a row, as the nrow(pairsDf) would reduce but
#the iterator would still run to the original nrow(pairsDf)
for(i in nrow(uniquePairs):1)
if(any(uniquePairs[,1]==uniquePairs[i,2] & uniquePairs[,2]==uniquePairs[i,1]))
uniquePairs = uniquePairs[-i,]
return(uniquePairs)
}
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