Description Usage Arguments Details Value Author(s) See Also Examples

An expression, involving the names of columns in a hyperframe, is evaluated separately for each row of the hyperframe.

1 2 3 4 |

`data` |
A hyperframe (object of class |

`expr` |
An |

`...` |
Ignored. |

`simplify` |
Logical. If |

`ee` |
Alternative form of |

`enclos` |
An environment in which to search for objects that are
not found in the hyperframe. Defaults to |

This function evaluates the expression `expr`

in each row
of the hyperframe `data`

. It is a method for the generic
function `with`

.

The argument `expr`

should be an **R** language expression
in which each variable name is either the name of a column in the
hyperframe `data`

, or the name of an object in the parent frame
(the environment in which `with`

was called.)
The argument `ee`

can be used as an alternative
to `expr`

and should be an expression object (of
class `"expression"`

).

For each row of `data`

, the expression will be evaluated
so that variables which are column names of `data`

are
interpreted as the entries for those columns in the current row.

For example, if a hyperframe `h`

has columns
called `A`

and `B`

, then `with(h, A != B)`

inspects
each row of `data`

in turn,
tests whether the entries in columns `A`

and `B`

are
equal, and returns the *n* logical values.

Normally a list of length
*n* (where *n* is the number of rows) containing the results
of evaluating the expression for each row.
If `simplify=TRUE`

and each result is a single atomic value,
then the result is a vector or factor
containing the same values.

and \rolf

1 2 3 | ```
# generate Poisson point patterns with intensities 10 to 100
H <- hyperframe(L=seq(10,100, by=10))
X <- with(H, rpoispp(L))
``` |

spatstat documentation built on May 30, 2017, 7:53 a.m.

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