Code
pb_logk()
Output
# A tibble: 23 x 3
name eqn log_k
<chr> <chr> <dbl>
1 "" Pb+2 + CO3-2 + H+ = PbHCO3+ 12.6
2 "" Pb+2 + 2CO3-2 = Pb(CO3)2-2 10.3
3 "" Pb+2 + CO3-2 = PbCO3 7.1
4 "" Pb+2 + 2Cl- = PbCl2 1.8
5 "" Pb+2 + Cl- = PbCl+ 1.59
6 "" Pb+2 + 3Cl- = PbCl3- 1.71
7 "" Pb+2 + 4Cl- = PbCl4-2 1.43
8 "" Pb+2 + 2H2O = Pb(OH)2 + 2H+ -16.9
9 "" 3Pb+2 + 4H2O = Pb3(OH)4+2 + 4H+ -23.9
10 "" 4Pb+2 + 4H2O = Pb4(OH)4+4 + 4H+ -20.9
# i 13 more rows
Code
pb_logk(kable_format = TRUE)
Output
# A tibble: 23 x 3
name eqn log_k
<chr> <chr> <dbl>
1 "" Pb^+2^ + CO~3~^-2^ + H^+^ = PbHCO~3~^+^ 12.6
2 "" Pb^+2^ + 2CO~3~^-2^ = Pb(CO~3~)~2~^-2^ 10.3
3 "" Pb^+2^ + CO~3~^-2^ = PbCO~3~ 7.1
4 "" Pb^+2^ + 2Cl^-^ = PbCl~2~ 1.8
5 "" Pb^+2^ + Cl^-^ = PbCl^+^ 1.59
6 "" Pb^+2^ + 3Cl^-^ = PbCl~3~^-^ 1.71
7 "" Pb^+2^ + 4Cl^-^ = PbCl~4~^-2^ 1.43
8 "" Pb^+2^ + 2H~2~O = Pb(OH)~2~ + 2H^+^ -16.9
9 "" 3Pb^+2^ + 4H~2~O = Pb~3~(OH)~4~^+2^ + 4H^+^ -23.9
10 "" 4Pb^+2^ + 4H~2~O = Pb~4~(OH)~4~^+4^ + 4H^+^ -20.9
# i 13 more rows
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