zones | R Documentation |
Organize data for multiple features for multiple management zones. Specifically, the data should describe the expected amount of each feature within each planning unit given each management zone. For example, the data could describe the occupancy (e.g., presence/absence), probability of occurrence, or abundance expected for each feature when each planning unit is allocated to a different zone.
zones(..., zone_names = NULL, feature_names = NULL)
... |
|
zone_names |
|
feature_names |
|
This function is used to store and organize data for use in a
conservation planning problem()
that has multiple management
zones.
In all cases, the data for each zone is input as a separate argument.
The correct arguments depends on the type of planning unit data
used when building the conservation planning problem()
.
problem()
will have terra::rast()
or sf::st_sf()
planning unitsterra::rast()
object can be supplied to specify the expected amount of
each feature within each planning unit under each management zone.
Data for each zone should be specified as separate
arguments, and the data for each feature in a given zone are specified
in separate layers in a terra::rast()
object.
Note that all layers for a given zone must have missing (NA
) values in
exactly the same cells.
problem()
will have sf::st_sf()
or data.frame
planning unitscharacter
vector containing column names can
be supplied to specify the expected amount of each feature under each
zone. Note that these columns must not contain any missing (NA
) values.
problem()
will have sf::st_sf()
, data.frame
, or
matrix
planning unitsdata.frame
object can be supplied to specify the
expected amount of each feature under each zone.
Following conventions used in Marxan, the
data.frame
object should contain the following columns.
integer
planning unit identifier.
integer
feature identifier.
numeric
amount of the feature in the
planning unit for a given zone.
Note that data for each zone are specified in a separate argument, and
the data contained in a single data.frame
object should correspond to
a single zone. Also, note that data are not required for all
combinations of planning units, features, and zones. The expected amount of
features in planning units under management zones that are
missing from the table are assumed to be zero.
A Zones
object containing data for each zone, and
the feature and zone names.
See problem()
for information on using this function to generate
a prioritization with multiple management zones.
## Not run:
# load planning unit data
sim_pu_raster <- get_sim_pu_raster()
zone_1 <- simulate_species(sim_pu_raster, 3)
zone_2 <- simulate_species(sim_pu_raster, 3)
# create zones using two SpatRaster objects
# each object corresponds to a different zone and each layer corresponds to
# a different species
z <- zones(
zone_1, zone_2,
zone_names = c("zone_1", "zone_2"),
feature_names = c("feature_1", "feature_2", "feature_3")
)
print(z)
# plot the rasters for the first zone in the Zones object
plot(
z[[1]],
main = c("Zone 1 feature 1", "Zone 1 feature 2", "Zone 1 feature 3")
)
# note that the do.call function can also be used to create a Zones object
# this method for creating a Zones object can be helpful when there are many
# management zones
l <- list(
zone_1, zone_2,
zone_names = c("zone_1", "zone_2"),
feature_names = c("feature_1", "feature_2", "feature_3")
)
z <- do.call(zones, l)
print(z)
# create zones using character vectors corresponding to column names
# of a data.frame or Spatial object that contain the amount
# of each species expected different management zones
z <- zones(
c("spp1_zone1", "spp2_zone1"),
c("spp1_zone2", "spp2_zone2"),
c("spp1_zone3", "spp2_zone3"),
zone_names = c("zone1", "zone2", "zone3"),
feature_names = c("spp1", "spp2")
)
print(z)
## End(Not run)
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