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abc = function (pars, init, prec, R.implementation=FALSE) {
# hydrological model no 1: the abc-model (acc. Vogel and Sankarasubramanian, WRR, 2003)
if(R.implementation){
# naive implementation in R (slow)
len = length(prec)
# get model parameters
a = as.numeric(pars['a'])
b = as.numeric(pars['b'])
c = as.numeric(pars['c'])
if((a+b)>1) stop('Implausible model parameters.')
# initialise model
G0 = as.numeric(init['G'])
P = prec
# These are our model equations (Q: stream flow, G: base flow)
# Q[t] = (1-a-b) * P[t] + c * G[t-1]
# G[t] = (1-c) * G[t-1] + a * P[t]
# Rekursionsvorschrift für Gt: Gt = G0*(1-c)^t + Summe_von_i=1_bis_t_über(a*Pi*(1-c)^(n-t))
# # die Zeitreihe für G wird um einen Zeitindex nach "rechts" verschoben (also G[1]=G0)
# # auf diese Weise kann dann Q ohne Schleife berechnet werden
G = rep(0,len)
Q = rep(0,len)
for(t in 1:len) {
G[t] = (1-c)*G0 + a*P[t]
Q[t] = (1-a-b)*P[t] + c*G0
G0 = G[t]
}
return(Q)
} else {
# Wrapper for the external abcmodel in Fortran (Flib.f03)
# Checks
if (any(is.na(prec))) { #stop("NA not allowed in input vector.")
return(rep(NA,length(prec)))
} else {
#for storages, use these default values if not specified from outside
if (length(init)==0) init=0
if (is.na(init['G'])) init['G']=0
# Call the fortran subroutine
out= .Fortran("abcmodel",
vect = as.double(prec),
vect_len = as.integer(length(prec)),
G0 = as.double(init['G']),
a = as.double(pars['a']),
b = as.double(pars['b']),
c = as.double(pars['c']),
Q = rep(as.double(0),length(prec))
)
return(list(q=out$Q, G = out$G0))
}
}
}
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