dbinomBCD | R Documentation |
Computes the probability mass function (p.m.f.) of the bivariate binomial conditionals distribution (BBCD) as defined by Ghosh, Marques, and Chakraborty (2025). The distribution is characterized by conditional binomial distributions for X
and Y
.
dbinomBCD(x, y, n1, n2, p1, p2, lambda)
x |
value of |
y |
value of |
n1 |
number of trials for |
n2 |
number of trials for |
p1 |
base success probability for |
p2 |
base success probability for |
lambda |
dependence parameter, must be positive. |
The joint p.m.f. of the BBCD is
P(X = x, Y = y) = K_B(n_1, n_2, p_1, p_2, \lambda) \binom{n_1}{x} \binom{n_2}{y} p_1^x p_2^y (1 - p_1)^{n_1 - x} (1 - p_2)^{n_2 - y} \lambda^{xy},
where x = 0, 1, \ldots, n_1
, y = 0, 1, \ldots, n_2
, and K_B(n_1, n_2, p_1, p_2, \lambda)
is the normalizing constant.
The probability P(X = x, Y = y)
.
Ghosh, I., Marques, F., & Chakraborty, S. (2025). A form of bivariate binomial conditionals distributions. Communications in Statistics - Theory and Methods, 54(2), 534–553. \Sexpr[results=rd]{tools:::Rd_expr_doi("10.1080/03610926.2024.2315294")}
pbinomBCD
rbinomBCD
MLEbinomBCD
# Compute P(X = 2, Y = 1) with n1 = 5, n2 = 5, p1 = 0.5, p2 = 0.4, lambda = 0.5
dbinomBCD(x = 2, y = 1, n1 = 5, n2 = 5, p1 = 0.5, p2 = 0.4, lambda = 0.5)
# Example with independence (lambda = 1)
dbinomBCD(x = 2, y = 1, n1 = 5, n2 = 5, p1 = 0.5, p2 = 0.4, lambda = 1.0)
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