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The average percentage of the total abundance per sample without an ITI classification (Gittenberger and van Loon, 2013) is given below:
if (tibble::has_name(d_mmi, "ITI_GROUP")) { d <- d_mmi %>% filter(!CARNIVORE | is.na(CARNIVORE)) %>% group_by(OBJECTID, HABITAT, YEAR) %>% mutate(N = sum(VALUE)) %>% filter(has_iti(taxon = TAXON, group = ITI_GROUP)) %>% summarise(ITI_MISSING = 100 * (1 - sum(VALUE) / unique(N))) } else { d <- d_mmi %>% filter(!CARNIVORE | is.na(CARNIVORE)) %>% group_by(OBJECTID, HABITAT, YEAR) %>% mutate(N = sum(VALUE)) %>% filter(has_iti(taxon = TAXON)) %>% summarise(ITI_MISSING = 100 * (1 - sum(VALUE) / unique(N))) } d %>% xtable %>% print(type = "html")
Note that in r sum(d$ITI_MISSING > 20)
cases, more than 20% of the total abundance does not have an ITI classification.
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