month_days: Return the number of days in a month given a certain CF...

In CFtime: Using CF-Compliant Calendars with Climate Projection Data

Return the number of days in a month given a certain CF calendar

Description

Given a vector of dates as strings in ISO 8601 or UDUNITS format and a CFTime object, this function will return a vector of the same length as the dates, indicating the number of days in the month according to the calendar specification. If no vector of days is supplied, the function will return an integer vector of length 12 with the number of days for each month of the calendar (disregarding the leap day for standard and julian calendars).

Usage

month_days(t, x = NULL)

Arguments

t	The CFTime instance to use.
x	character. An optional vector of dates as strings with format YYYY-MM-DD. Any time part will be silently ingested.

Value

A vector indicating the number of days in each month for the vector of dates supplied as argument x. Invalidly specified dates will result in an NA value. If no dates are supplied, the number of days per month for the calendar as a vector of length 12.

See Also

When working with factors generated by CFfactor(), it is usually better to use CFfactor_units() as that will consider leap days for non-era factors. CFfactor_units() can also work with other time periods and calendar units, such as "hours per month", or "days per season".

Examples

dates <- c("2021-11-27", "2021-12-10", "2022-01-14", "2022-02-18")
t <- CFtime("days since 1850-01-01", "standard")
month_days(t, dates)

t <- CFtime("days since 1850-01-01", "360_day")
month_days(t, dates)

t <- CFtime("days since 1850-01-01", "all_leap")
month_days(t, dates)

month_days(t)

CFtime documentation built on April 12, 2025, 5:07 p.m.