Nothing
## Seems we really lack a good, fast, generic way to find-
## and-replace arbitrary nodes in XML..
## should identify all ReferencesGroup elements, and replace them with copy of the
## node that they reference.
resolve_references <- function(eml) {
## Ideally, just do this all in XML manipulation. Serialize to XML,
## substitute, and then re-parse.
doc <- XML::xmlParse(write_eml(eml))
## FIXME: Would need to do xmlRoot and then find all <references> recursively.
## This is just a copy of the nodes; changing these values doesn't change `doc`
refs <- XML::xpathApply(doc, "//references")
replace <- lapply(refs, function(ref) {
id <- xmlValue(ref)
nodes <- XML::xpathApply(doc, sprintf("//*[@id = '%s']", id))
})
}
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