clock-invalid | R Documentation |
This family of functions is for working with invalid calendar dates.
Invalid dates represent dates made up of valid individual components, which
taken as a whole don't represent valid calendar dates. For example, for
year_month_day()
the following component ranges are valid:
year: [-32767, 32767]
, month: [1, 12]
, day: [1, 31]
.
However, the date 2019-02-31
doesn't exist even though it is made up
of valid components. This is an example of an invalid date.
Invalid dates are allowed in clock, provided that they are eventually
resolved by using invalid_resolve()
or by manually resolving them through
arithmetic or setter functions.
invalid_detect(x)
invalid_any(x)
invalid_count(x)
invalid_remove(x)
invalid_resolve(x, ..., invalid = NULL)
x |
A calendar vector. |
... |
These dots are for future extensions and must be empty. |
invalid |
One of the following invalid date resolution strategies:
Using either If If |
Invalid dates must be resolved before converting them to a time point.
It is recommended to use "previous"
or "next"
for resolving invalid
dates, as these ensure that relative ordering among x
is maintained.
This is a often a very important property to maintain when doing time series
data analysis. See the examples for more information.
invalid_detect()
: Returns a logical vector detecting invalid dates.
invalid_any()
: Returns TRUE
if any invalid dates are detected.
invalid_count()
: Returns a single integer containing the number of
invalid dates.
invalid_remove()
: Returns x
with invalid dates removed.
invalid_resolve()
: Returns x
with invalid dates resolved using the
invalid
strategy.
# Invalid date
x <- year_month_day(2019, 04, 30:31, c(3, 2), 30, 00)
x
invalid_detect(x)
# Previous valid moment in time
x_previous <- invalid_resolve(x, invalid = "previous")
x_previous
# Previous valid day, retaining time of day
x_previous_day <- invalid_resolve(x, invalid = "previous-day")
x_previous_day
# Note that `"previous"` retains the relative ordering in `x`
x[1] < x[2]
x_previous[1] < x_previous[2]
# But `"previous-day"` here does not!
x_previous_day[1] < x_previous_day[2]
# Remove invalid dates entirely
invalid_remove(x)
y <- year_quarter_day(2019, 1, 90:92)
y
# Overflow rolls forward by the number of days between `y` and the previous
# valid date
invalid_resolve(y, invalid = "overflow")
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