View source: R/step-subset-slice.R
slice.dtplyr_step | R Documentation |
These are methods for the dplyr slice()
, slice_head()
, slice_tail()
,
slice_min()
, slice_max()
and slice_sample()
generics. They are
translated to the i
argument of [.data.table
.
Unlike dplyr, slice()
(and slice()
alone) returns the same number of
rows per group, regardless of whether or not the indices appear in each
group.
## S3 method for class 'dtplyr_step'
slice(.data, ..., .by = NULL)
## S3 method for class 'dtplyr_step'
slice_head(.data, ..., n, prop, by = NULL)
## S3 method for class 'dtplyr_step'
slice_tail(.data, ..., n, prop, by = NULL)
## S3 method for class 'dtplyr_step'
slice_min(.data, order_by, ..., n, prop, by = NULL, with_ties = TRUE)
## S3 method for class 'dtplyr_step'
slice_max(.data, order_by, ..., n, prop, by = NULL, with_ties = TRUE)
.data |
A |
... |
For Provide either positive values to keep, or negative values to drop. The values provided must be either all positive or all negative. Indices beyond the number of rows in the input are silently ignored. For |
.by, by |
< |
n, prop |
Provide either A negative value of |
order_by |
< |
with_ties |
Should ties be kept together? The default, |
library(dplyr, warn.conflicts = FALSE)
dt <- lazy_dt(mtcars)
dt %>% slice(1, 5, 10)
dt %>% slice(-(1:4))
# First and last rows based on existing order
dt %>% slice_head(n = 5)
dt %>% slice_tail(n = 5)
# Rows with minimum and maximum values of a variable
dt %>% slice_min(mpg, n = 5)
dt %>% slice_max(mpg, n = 5)
# slice_min() and slice_max() may return more rows than requested
# in the presence of ties. Use with_ties = FALSE to suppress
dt %>% slice_min(cyl, n = 1)
dt %>% slice_min(cyl, n = 1, with_ties = FALSE)
# slice_sample() allows you to random select with or without replacement
dt %>% slice_sample(n = 5)
dt %>% slice_sample(n = 5, replace = TRUE)
# you can optionally weight by a variable - this code weights by the
# physical weight of the cars, so heavy cars are more likely to get
# selected
dt %>% slice_sample(weight_by = wt, n = 5)
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