| date3to1 | R Documentation | 
Combine or split Date into a specified format
date3to1(data, out.format = "%Y-%m-%d", col.YMD = 1:3, as.vector = FALSE)
date1to3(
  data,
  in.format = "%Y-%m-%d",
  date.col = 1,
  out.cols = c("%Y", "%m", "%d")
)
data | 
 data frame object  | 
out.format | 
 date output format  | 
col.YMD | 
 columns to combine for Year, Month and Day  | 
as.vector | 
 return output as vector, or leave as data frame  | 
in.format | 
 date input format  | 
date.col | 
 numeric value of column within the dataset that contains the dates  | 
out.cols | 
 cols to of date items to split. Make sure to conform to date formats. See "NOTE" section for date formats  | 
NOTE for date3to1
The three input columns corresponding to "Year Month Day" must be numeric values. 
For example, Do not provide the month variable as non-numeric such as "Mar", "Jul", or "Jan". 
If the values of the columns are non-numeric, the results will return an "NA" in the output.date column.
date derived from combining values from three columns of a data frame
DATE FORMATS IN R
| Date Specification | Description | Example | ||
| %a | Abbreviated weekday | Sun, Thu | ||
| %A | Full weekday | Sunday | ||
| %b | Abbreviated month | May, Jul | ||
| %B | Full month | March, July | ||
| %d | Day of the month | 27, 07 | ||
| %j | Day of the year | 148, 188 | ||
| %m | Month | 05, 07 | ||
| %U | Week, with Sunday as first day | 22, 27 | ||
| %w | Weekday, Sunday is 0 | 0, 4 | ||
| %W | Week, with Monday as first day | 21, 27 | ||
| %x | Date, locale-specific | |||
| %y | Year without century | 84, 05 | ||
| %Y | Year with century | 1984, 2005 | ||
| %C | Century | 19, 20 | ||
| %D | Date formatted %m/%d/%y | 07/17/23 | ||
| %u | Weekday, Monday is 1 | 7, 4 | ||
Adapted from Ecfun R package
# EXAMPLES FOR date3to1
data0 <- data.frame(y=c(NA, -1, 2001:2009),
m=c(1:2, -1, NA, 13, 2, 12, 6:9),
d=c(0, 0:6, NA, -1, 32) )
head(data0)
# combine and convert to date
# return as data frame
date3to1(data0)
# combine and convert to date
# return as vector
date3to1(data0, as.vector = TRUE) #eg. 2004-02-04
# combine and convert to date in the format DD_MM_YYYY
date3to1(data0, out.format = "%d_%m_%Y") #eg. 04_02_1974
# combine and convert to date in the format MM_DD_YY
date3to1(data0, out.format = "%m_%d_%y") #eg. 02_04_74
# combine and convert to date in the various date formats
date3to1(data0, out.format = "%B %d, %y") #eg. February 04, 74
date3to1(data0, out.format = "%a, %b %d, %Y") #eg. Mon, Feb 04, 1974
date3to1(data0, out.format = "%A, %B %d, %Y") #eg. Monday, February 04, 1974
date3to1(data0, out.format = "Day %j in Year %Y") #eg. Day 035 in Year 1974
date3to1(data0, out.format = "Week %U in %Y") #eg. Week 05 in 1974
date3to1(data0, out.format = "Numeric month %m in Year %Y") #eg. Numeric month 02 in Year 1974
# EXAMPLES FOR date1to3
data1 <- data.frame(Full.Dates =
                      c("2023-02-14",NA,NA,
                        "2002-12-04","1974-08-04",
                        "2008-11-10"))
head(data1)
# split date with default settings
# return as data frame with columns
# for day(d), month(m) and year(Y)
date1to3(data1)
# split date in the format and only return year in YYYY
date1to3(data1, out.cols = "%Y") #eg. 2002, 2023
# split date in the format and only return month in m
date1to3(data1, out.cols = "%m") #eg. 02, 12, 08
# split date in the format and return multiple date formats colums
date1to3(data1, out.cols = c("%B","%d") )
date1to3(data1, out.cols = c("%a","%b","%y") )
date1to3(data1, out.cols = c("%A","%B","%Y","%y") )
date1to3(data1, out.cols = c("%j","%Y","%y","%m") )
date1to3(data1, out.cols = c("%U","%Y","%y","%x") )
date1to3(data1, out.cols = c("%m","%Y","%y","%C") )
Add the following code to your website.
For more information on customizing the embed code, read Embedding Snippets.