solvecost_labor | R Documentation |
This function takes number of FTE and annual $/FTE and determines labor cost
solvecost_labor(fte, cost, time = "day")
fte |
Number of FTEs. Can be decimal. |
cost |
$/year per FTE |
time |
Desired output units, one of c("day", "month", "year"). Defaults to "day". |
A numeric value for labor $/time.
laborcost <- solvecost_labor(1.5, 50000)
library(dplyr)
cost_data <- tibble(
fte = seq(1, 10, 1)
) %>%
mutate(costs = solvecost_labor(fte = fte, cost = .08))
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