knitr::opts_chunk$set( collapse = TRUE, comment = "#>" )
The purpose of this vignette is to learn how to estimate trophic position of a species using stable isotope data ($\delta^{13}C$ and $\delta^{15}N$). We can estimate trophic position using a two source model that is based on equations from Post (2002) and Vander Zaden and Vadeboncoeur (2002).
The equations for a two source model consists of the following:
$$ \alpha = \frac{(\delta^{13}C_c - \delta^{13}C_{b2})}{(\delta^{13}C_{b1}-\delta^{13}C_{b2})} $$
$\delta^{15}C_c$ is the isotope value of the consumer, $\delta^{15}C_{b1}$ is the mean isotope value of the first baseline, $\delta^{15}C_{b2}$ is the mean isotope value of the second baseline. For aquatic ecosystems, often $\delta^{15}C_{b1}$ is from a benthic source and $\delta^{15}C_{b2}$ is from a pelagic source. Lastly, $\alpha$ is the proportion of carbon that comes from each source and should be bound by 0 and 1. We will see later that this does not always happen which can be problematic with Heuvel et al., (2024) proposing a new method to correct (i.e., scale) these values. Estimates of $\alpha$ are used in the two source trophic postion equation below.
$$ \text{Trophic Position} = \lambda + \frac{(\delta^{15}N_c - [(\delta^{15}N_{b1} \times \alpha) - (\delta^{15}N_{b1} \times (1 - \alpha))]}{\Delta N} $$
Where $\lambda$ is the trophic position of the baseline (e.g., 2
),
$\delta^{15}N_c$ is the $\delta^{15}N$ of the consumer, $\delta^{15}N_{b1}$
is the mean $\delta^{15}N$ of the first baseline (e.g., benthic),
$\delta^{15}N_{b2}$
is the mean $\delta^{15}N$ of the second baseline (e.g., pelagic), $\alpha$
is estimated above, and $\Delta N$ is the trophic enrichment factor (e.g., 3.4).
There is a variation of this model that uses a mixing model to consider different trophic position for each baseline ($\lambda$). The equation replaces $\lambda$ with the following:
$$ \lambda = (\lambda_1 \times \alpha) - (\lambda_2\times (1 - \alpha)) $$
Where $\lambda_1$ is the trophic level of the first baseline (e.g., 2), $\lambda_2$ is the trophic level of the second baseline (e.g., 2.5), and $\alpha$ is from above. Only use this replacement equation for $\lambda$ if you have baselines from two different trophic levels.
To use these model with a Bayesian framework, we need to rearrange the equation for $\alpha$ to the following:
$$ \delta^{13}C_c = \alpha \times (\delta^{13}C_{b1} - \delta^{13}C_{b2}) + \delta^{13}C_{b2} $$
Estimates of $\alpha$ are then used in the rearranged equation for trophic position below.
$$ \delta^{15}N_c = \Delta N \times (\text{Trophic Position} - \lambda) + \delta^{15}N_{b1} \times \alpha + \delta^{15}N_{b2} \times (1 - \alpha) $$
The function two_source_model()
uses both of these rearranged equation. If using
baselines from two different trophic levels, you can set the argument lambda
to 2
to replace $\lambda$ (l1
) with the mixing model for $\lambda$ above.
First we need to organize the data prior to running the model. To do this work we will use {dplyr} and {tidyr} but we could also use {data.table}.
When running the model we will use {trps} and {brms}.
Once we have run the model we will use {bayesplot} to assess models and then extract posterior draws using {tidybayes}. Posterior distributions will be plotted using {ggplot2} and {ggdist} with colours provided by {viridis}.
First we load all the packages needed to carry out the analysis.
{ library(bayesplot) library(brms) library(dplyr) library(ggplot2) library(ggdist) library(grid) library(tidybayes) library(tidyr) library(trps) library(viridis) }
In {trps} we have several data sets, they include stable isotope data ($\delta^{13}C$ and $\delta^{15}N$) for a consumer, lake trout (Salvelinus namaycush), a benthic baseline, amphipods, and a pelagic baseline, dreissenids, for an ecoregion in Lake Ontario.
We check out each data set with the first being the consumer.
consumer_iso
We can see that this data set contains the common_name
of the consumer, the ecoregion
samples were collected from, and $\delta^{13}C$ (d13c
) and $\delta^{15}N$ (d15n
).
Next we check out the benthic baseline data set.
baseline_1_iso
We can see that this data set contains the common_name
of the baseline, the ecoregion
samples were collected from, and $\delta^{13}C$ (d13c_b1
) and $\delta^{15}N$ (d15n_b1
).
Next we check out the pelagic baseline data set.
baseline_2_iso
We can see that this data set contains the common_name
of the baseline, the ecoregion
samples were collected from, and $\delta^{13}C$ (d13c_b2
) and $\delta^{15}N$ (d15n_b2
).
Now that we understand the data we need to combine both data sets to estimate trophic position for our consumer.
To do this we first need to make an id
column in each data set, which will allow us to join them together. We first arrange()
the data by ecoregion
and common_name
. Next we group_by()
the same variables, and add id
for each grouping using row_number()
. Always ungroup()
the data.frame
after using group_by()
. Lastly, we use dplyr::select()
to rearrange the order of the columns.
Let's first add id
to consumer_iso
data frame.
con_ts <- consumer_iso %>% arrange(ecoregion, common_name) %>% group_by(ecoregion, common_name) %>% mutate( id = row_number() ) %>% ungroup() %>% dplyr::select(id, common_name:d15n)
You will notice that I have renamed this object to con_ts
this is because
we are modifying consumer_iso
and should make
a new object. I have continued with the same renaming nomenclature for objects
below.
Next let's add id
to baseline_1_iso
data frame.
For joining purposes we are going to drop common_name
from this data frame.
b1_ts <- baseline_1_iso %>% arrange(ecoregion, common_name) %>% group_by(ecoregion, common_name) %>% mutate( id = row_number() ) %>% ungroup() %>% dplyr::select(id, ecoregion:d15n_b1)
Next let's add id
to baseline_2_iso
data frame. For joining purposes
we are going to drop common_name
from this data frame.
b2_ts <- baseline_2_iso %>% arrange(ecoregion, common_name) %>% group_by(ecoregion, common_name) %>% mutate( id = row_number() ) %>% ungroup() %>% dplyr::select(id, ecoregion:d15n_b2)
Now that we have the consumer and baseline data sets in a consistent
format we can join them by "id"
and "ecoregion"
using left_join()
from {dplyr}.
combined_iso_ts <- con_ts %>% left_join(b1_ts, by = c("id", "ecoregion")) %>% left_join(b2_ts, by = c("id", "ecoregion"))
We can see that we have successfully combined our consumer and baseline data.
We need to do one last thing prior to analyzing the data, and that is
calculate the mean $\delta^{13}C$ (c1
and c2
) and $\delta^{15}N$ (n1
and
n2
) for the baselines and add in the constant $\lambda$ (l1
) to our
data frame. We do this by using groub_by()
to group the data by our two groups,
then using mutate()
and mean()
to calculate the mean values.
Important note, to run the model successfully, columns need to be
named d13c
, c1
, c2
, d15n
, n1
, n2
, and l1
with l2
needed if using
two $\lambda s$.
combined_iso_ts_1 <- combined_iso_ts %>% group_by(ecoregion, common_name) %>% mutate( c1 = mean(d13c_b1, na.rm = TRUE), n1 = mean(d15n_b1, na.rm = TRUE), c2 = mean(d13c_b2, na.rm = TRUE), n2 = mean(d15n_b2, na.rm = TRUE), l1 = 2 ) %>% ungroup()
Let's view our combined data.
combined_iso_ts_1
It is now ready to be analyzed!
We can now estimate trophic position for lake trout in an ecoregion of Lake Ontario.
There are a few things to know about running a Bayesian analysis, I suggest reading these resources:
Bayesian analyses rely on supplying uninformed or informed prior distributions
for each parameter (coefficient; predictor) in the model. The default
informed priors for a two source model are the following, $\alpha$ is bound
by 0 and 1 and assumes an unformed beta distribution ($\alpha = 1$ and $\beta = 1$),
$\Delta N$ assumes a normal distribution (dn
; $\mu = 3.4$; $\sigma = 0.25$),
trophic position assumes a uniform distribution (lower bound = 2 and
upper bound = 10), $\sigma$ assumes a uniform distribution (lower bound = 0
and upper bound = 10), and if informed priors are desired for
$\delta^{13}C_{b1}$
and $\delta^{13}C_{b2}$ (c1
and c2
; $\mu = -21$ and $-26$; $\sigma = 1$),
and
$\delta^{15}N_{b1}$
and $\delta^{15}N_{b2}$ (n1
and n2
; $\mu = 8$ and $9.5$; $\sigma = 1$),
we can set the argument bp
to TRUE
in all two_source_
functions.
You can change these default priors using two_source_priors_params()
, however,
I would suggest becoming familiar with Bayesian analyses, your study species,
and system prior to adjusting these values.
It is important to always run the model with at least 2 chains. If the model does not converge you can try to increase the following:
The amount of samples that are burned-in (discarded; in brm()
this can be controlled by the argument warmup
)
The number of iterative samples retained (in brm()
this can be controlled by the argument iter
).
The number of samples drawn (in brm()
this is controlled by the argument thin
).
The adapt_delta
value using control = list(adapt_delta = 0.95)
.
When assessing the model we want $\hat R$ to be 1 or within 0.05 of 1, which indicates that the variance among and within chains are equal (see {rstan} documentation on $\hat R$), a high value for effective sample size (ESS), trace plots to look "grassy" or "caterpillar like," and posterior distributions to look relatively normal.
We will use functions from {trps} that drop into a {brms} model. These functions are two_source_model()
which provides brm()
the formula structure needed to run a one source model. Next brm()
needs the structure of the priors which is supplied to the prior
argument using two_source_priors()
. Lastly, values for these priors are supplied through the stanvars
argument using two_source_priors_params()
. You can adjust the mean ($\mu$), variance ($\sigma$), or upper and lower bounds (lb
and ub
) for each prior of the model using two_source_priors_params()
, however, only adjust priors if you have a good grasp of Bayesian frameworks and your study system and species.
Let's run the model!
model_output_ts <- brm( formula = two_source_model(), prior = two_source_priors(), stanvars = two_source_priors_params(), data = combined_iso_ts_1, family = gaussian(), chains = 2, iter = 4000, warmup = 1000, cores = 4, seed = 4, control = list(adapt_delta = 0.95) )
Let's view the summary of the model.
model_output_ts
We can see that $\hat R$ is 1 meaning that variance among and within chains are equal (see {rstan} documentation on $\hat R$) and that ESS is quite large. Overall, this means the model is converging and fitting accordingly.
Let's view trace plots and posterior distributions for the model.
plot(model_output_ts)
We can see that the trace plots look "grassy" meaning the model is converging!
We can check how well the model is predicting the $\delta^{13}C$ of the consumer
using pp_check()
from {bayesplot}
.
pp_check(model_output_ts, resp = "d13c")
We can see that posteriors draws ($y_{rep}$; light lines) are not
effectively modeling $\delta^{13}C$ of the consumer ($y$; dark line).
We can correct (i.e., scale) these values using another model two_source_model_ar()
that uses an equation in
Heuvel et al., (2024)
that corrects (i.e., scales) $\alpha$ providing better and more meaningful
estimates. I will demostrate how to use this model in
Estimate Trophic Position - Two Source Model - ar. .
Next We can check how well the model is predicting the $\delta^{15}N$ of the consumer
using pp_check()
from {bayesplot}
.
pp_check(model_output_ts, resp = "d15n")
We can see that posteriors draws ($y_{rep}$; light lines) are effectively modeling $\delta^{15}N$ of the consumer ($y$; dark line).
Let's again look at the summary output from the model.
model_output_ts
We can see that $\alpha$ is estimated to be 0.05
with l-95% CI
of 0.00
and u-95% CI
of 0.19
. These values do not make a lot sense as
this indicates the lake trout are heavily using
benthic resource which we know from previous work is not true.
In another vignette, I'll demonstrate how to use a model
that corrects or scales $\alpha$ appropriately using
an equation in Heuvel et al. (2024)
Moving down to the trophic position model we can see
$\Delta N$ is estimated to be 3.38
with l-95% CI
of 2.89
,
and u-95% CI
of 3.85
. If we move down to trophic position (tp
)
we see trophic position is estimated to be 4.57
with l-95% CI
of 4.20
, and u-95% CI
of 5.02
.
We use functions from {tidybayes}
to do this work. First we look at the the names of the variables we want to extract using get_variables()
.
get_variables(model_output_ts)
You will notice that "b_d13c_alpha_Intercept"
and "b_d15n_tp_Intercept"
are
the names of the variable that we are wanting to extract.
We extract posterior draws using gather_draws()
, and
rename "b_d15n_tp_Intercept"
to tp
and "b_d13c_alpha_Intercept"
to
alpha
.
post_draws <- model_output_ts %>% gather_draws(b_d13c_alpha_Intercept, b_d15n_tp_Intercept) %>% mutate( ecoregion = "Embayment", common_name = "Lake Trout", .variable = case_when( .variable %in% "b_d15n_tp_Intercept" ~ "tp", .variable %in% "b_d13c_alpha_Intercept" ~ "alpha" ) ) %>% dplyr::select(common_name, ecoregion, .chain:.value)
Let's view the post_draws
post_draws
We can see that this consists of seven variables:
ecoregion
common_name
.chain
.iteration
(number of sample after burn-in).draw
(number of samples from iter
).variable
(this will have different variables depending on what is supplied to gather_draws()
).value
(estimated value)Considering we are likely using this information for a paper or presentation, it is nice to be able to report the median and credible intervals (e.g., equal-tailed intervals; ETI). We can extract and export these values using gather_draws()
and median_qi
from {tidybayes}.
We rename d15n_tp_Intercept
to tp
and b_d13c_alpha_Intercept
to alpha
,
add the grouping columns, round all columns that are numeric to two decimal
points using mutate_if()
, and rearrange the order of the columns
using dplyr::select()
.
medians_ci <- model_output_ts %>% gather_draws(b_d13c_alpha_Intercept, b_d15n_tp_Intercept) %>% median_qi() %>% mutate( ecoregion = "Embayment", common_name = "Lake Trout", .variable = case_when( .variable %in% "b_d15n_tp_Intercept" ~ "tp", .variable %in% "b_d13c_alpha_Intercept" ~ "alpha" ) ) %>% mutate_if(is.numeric, round, digits = 2)
Let's view the output.
medians_ci
I like to use {openxlsx} to export these values into a table that I can use for presentations and papers. For the vignette I am not going to demonstrate how to do this but please check out {openxlsx}
.
Now that we have our posterior draws extracted we can plot them. To analyze a single species or group, I like using density plots.
For this example we first plot the density for posterior draws using
geom_density()
.
ggplot(data = post_draws, aes(x = .value)) + geom_density() + facet_wrap(~ .variable, scale = "free") + theme_bw(base_size = 15) + theme( panel.grid = element_blank(), strip.background = element_blank(), ) + labs( x = "P(Estimate | X)", y = "Density" )
Next we plot it as a point interval plot using stat_pointinterval()
.
ggplot(data = post_draws, aes(y = .value, x = common_name)) + stat_pointinterval() + facet_wrap(~ .variable, scale = "free") + theme_bw(base_size = 15) + theme( panel.grid = element_blank(), strip.background = element_blank(), ) + labs( x = "P(Estimate | X)", y = "Density" )
Congratulations we have estimated the trophic position for Lake Trout!
Again, you will notice estimates of $\alpha$ do not really make sense which
we can correct (i.e., scale) using another model two_source_model_ar()
that
uses an equation in
Heuvel et al. (2024)
You can use iterative process to produce estimates of trophic position for more than one group (e.g., comparing trophic position among species or in this case different ecoregions) using iterative processes that are demonstrated in estimate trophic position - one source - multiple groups.
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