partition: Divide a grid of cells into partitions containing individual...

In unpivotr: Unpivot Complex and Irregular Data Layouts

Divide a grid of cells into partitions containing individual tables

Description

Given the positions of corner cells that mark individual tables in a single spreadsheet, partion() works out which table cells belong to which corner cells. The individual tables can then be worked on independently.

partition() partitions along both dimensions (rows and columns) at once. partition_dim() partitions along one dimension at a time.

Usage

partition(cells, corners, align = "top_left", nest = TRUE, strict = TRUE)

partition_dim(positions, cutpoints, bound = "upper")

Arguments

cells	Data frame or tbl, the cells to be partitioned, from as_cells() or tidyxl::xlsx_cells().
corners	usually a subset of cells, being the corners of individual tables. Can also be cells that aren't among cells, in which case see the strict argument.
align	Character, the position of the corner cells relative to their tables, one of "top_left" (default), "top_right", "bottom_left", "bottom_right".
nest	Logical, whether to nest the partitions in a list-column of data frames.
strict	Logical, whether to omit partitions that don't contain a corner cell.
positions	Integer vector, the positions of cells (either the row position or the column position), which are to be grouped between cutpoints.
cutpoints	Integer vector. The positions will be separated into groups either side of each cutpoint.
bound	One of "upper" or "lower", controls whether cells that lie on a cutpoint are should be grouped with cells below or above the cutpoint. For example, if column 5 is a cutpoint, and a cell is in column 5, "lower" would group it with cells in columns 1 to 4, whereas "upper" would group it with cells in columns 6 to 10. This is so that you can use cells at the bottom or the right-hand side of a table as the cutpoints (either of which would be 'upper' bounds because row and column numbers count from 1 in the top-left row and column). When "upper", any cell_positions above the first cutpoint will be in group 0; when "lower", any cell_positions below the final cutpoint will be 0.

Value

partition_dim() returns an integer vector, numbering the groups of cells. Group 0 represents the cells above the first cutpoint (when bound = "upper"), or below the first cutpoint (when bound = "lower"). The other groups are numbered from 1, where group 1 is adjacent to group 0.

partition_dim() returns an integer vector, numbering the groups of cells. Group 0 represents the cells above the first cutpoint (when bound = "upper"), or below the first cutpoint (when bound = "lower"). The other groups are numbered from 1, where group 1 is adjacent to group 0. Divide a grid of cells into chunks along both dimensions

Functions

• partition_dim(): Divide a grid of cells into chunks along one dimension

Examples

# The `purpose` dataset, represented in four summary tables
multiples <- purpose$small_multiples
rectify(multiples, character, numeric)

# The same thing in its raw 'melted' form that can be filtered
multiples

# First, find the cells that mark a corner of each table
corners <-
  dplyr::filter(multiples,
                !is.na(character),
                !(character %in% c("Sex", "Value", "Female", "Male")))

# Then find out which cells fall into which partition
partition(multiples, corners)

# You can also use bottom-left corners (or top-right or bottom-right)
bl_corners <- dplyr::filter(multiples, character == "Male")
partition(multiples, bl_corners, align = "bottom_left")

# To complete the grid even when not all corners are supplied, use `strict`
bl_corners <- bl_corners[-1, ]
partition(multiples, bl_corners, align = "bottom_left")
partition(multiples, bl_corners, align = "bottom_left", strict = FALSE)
# Given a set of cells in rows 1 to 10, partition them at the 3rd, 5th and 7th
# rows.
partition_dim(1:10, c(3, 5, 7))

# Given a set of cells in columns 1 to 10, partition them at the 3rd, 5th and
# 7th column.  This example is exactly the same as the previous one, to show
# that the function works the same way on columns as rows.
partition_dim(1:10, c(3, 5, 7))

# Given a set of cells in rows 1 to 10, partition them at the 3rd, 5th and
# 7th rows, aligned to the bottom of the group.
partition_dim(1:10, c(3, 5, 7), bound = "lower")

# Non-integer row/column numbers and cutpoints can be used, even though they
# make no sense in the context of partioning grids of cells.  They are
# rounded towards zero first.
partition_dim(1:10 - .5, c(3, 5, 7))
partition_dim(1:10, c(3, 5, 7) + 1.5)

unpivotr documentation built on Jan. 23, 2023, 5:40 p.m.