fh_raster_transform: function to perform a raster::extract on very large data sets

In EricKrg/ForestHealth: What the Package Does (One Line, Title Case)

Description

function to perform a raster::extract on very large data sets

Usage

fh_raster_transform(in_layerStack, parallel, no_cores, transform_eq)

Arguments

in_layerStack	- a raster brick or stack
transfrom_eq	- equation to manipulate the cell values i.e. "(x - 10000) /10000" x represents the cell value

Details

takes a layer stack/brick an transforms all layers-pixel values provide a transformation eq like: transform_eq = "(x-10000) / 10000"

Author(s)

Eric Krueger

Examples

## Not run: 
r <- r2 <- raster::raster(ncol=10, nrow=10)
r <- raster::setValues(r,1:raster::ncell(r))
r2 <- raster::setValues(r2,10)
raster_brick <- raster::brick(r,r2)
fh_raster_transform(in_layerStack = raster_brick,
                 transform_eq = "(x + 10) / 2") # adds 10 to each cell

## End(Not run)

EricKrg/ForestHealth documentation built on May 23, 2019, 6:08 p.m.