#########################################
#find common elements count of m groups 2 cv
########################################
perm <- function(n,k){choose(n,k) * factorial(k)}
statCommonElementCount<-function(mgroups){
counts<-rep(NA, perm(length(mgroups),2)/2)
index <-1
for(i in 1:(length(mgroups)-1)){
group1<-mgroups[[i]]
for(j in (i+1):length(mgroups)){
group2<-mgroups[[j]]
counts[index] <- length(intersect(group1[[1]],group2[[1]]))
index<-index+1
}
}
return(counts)
}
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