#' @section Process Haar WV First Derivative:
#' Taking the derivative with respect to \eqn{Q^2}{Q^2} yields:
#' \deqn{\frac{\partial }{{\partial {Q^2}}}\nu _j^2\left( {{Q^2}} \right) = \frac{6}{{\tau _j^2}}}{d/dQ2 nu[j]^2 (Q2) = (6) / (tau[j]^2)}
Add the following code to your website.
For more information on customizing the embed code, read Embedding Snippets.