#' @section Process Haar WV First Derivative:
#' Taking the derivative with respect to \eqn{\sigma^2}{sigma^2} yields:
#' \deqn{\frac{\partial }{{\partial {\sigma ^2}}}\nu _j^2\left( {{\sigma ^2}} \right) = \frac{1}{{{\tau _j}}}}{d/dsigma2 nu[j]^2(sigma2) = 1/tau[j]}
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