View source: R/ch.maxAveComb.r

ch.maxAveComb | R Documentation |

This function combines a list into a single vector controling the percent of observations devoted to the list element with the max median.

```
ch.maxAveComb(list.data, probMax = 0.5)
```

`list.data` |
A list with each element filled with numbers. |

`probMax` |
A probability that specifies the probability of samples that should be devoted to the column with the max(median()). When probMax = 0, the column with the max(median()) has no influence on either the average or above and beyond the average. When probMax = 0.5, the column with the max(median()) is 50 percent of the output vector. This is simply collapsing into a vector (as.vector) when there are only 2 vectors in the list. But it will have an outsized influence if there are more than two vector in the list. When probMax = 1, the column with the max(median()) is 100 percent of the output vector. DEFAULT = 0.5 (equal influence for two vectors)(probMax = .8 will produce a distribution in which .4 of the total are all the items (including the max) and .6 of the total are MAX items - when there are only two vectors in the list). Use ch.getProbMax() to calculate the appropriate probMax. |

a vector of values that combines all the columns in df.data with probMax samples devoted to the column with the max(median())

```
ch.maxAveComb (list.data, probMax = .8)
```

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