In charlotte-ngs/lbgfs2021: Livestock Breeding and Genomics (ETHZ) - Fall Semester 2021

knitr::opts_chunk$set(echo = TRUE)

Pedigree

nr_animal <- 6
tbl_pedigree <- tibble::tibble(Calf = c(1:nr_animal),
                               Sire = c(NA, NA, NA, 1 ,3, 4),
                               Dam = c(NA, NA, NA, 2, 2, 5))
tbl_pedigree

Numerator Relationship Matrix

We call the numerator relationship matrix $A$. The computation of the elements of $A$ are done separately for

1. the diagnoal elements $(A)_{ii}$ and
2. the off-diagonal elements $(A)_{ij}$ for $i \ne j$

First all elements of the matrix $A$ are initialized to $0$

A = matrix(0, nrow = nr_animal, ncol = nr_animal)
A

Diagonal Elements

Computation: $(A){ii} = (1 + F_i)$ and $F_i = 1/2 (A){sd}$

i <- 1
s <- tbl_pedigree$Sire[i]
d <- tbl_pedigree$Dam[i]

Fi <- ifelse((is.na(s) | is.na(d)), 0, 0.5 * A[s,d])
A[i,i] <- 1+Fi
A

Off-diagonal Elements

Off-diagonal $(A){ij} = 1/2 (A){io} + 1/2 (A)_{iq}$ where $o$ and $q$ are parents of $j$

for (j in (i+1):6){
  o <- tbl_pedigree$Sire[j]
  q <- tbl_pedigree$Dam[j]
  Aio <- ifelse(is.na(o), 0, A[i,o])
  Aiq <- ifelse(is.na(q), 0, A[i,q])
  A[i,j] <- 0.5 * Aio + 0.5 * Aiq
}
A[(i+1):6,i] <- A[i,(i+1):6]
A

Problem 1: Numerator Relationship Matrix

Use the above steps of computation for the complete matrix.

Hint

• Construct a loop with loop-variable $i$ that runs over all the rows of the matrix $A$.

Solution

Check Result

The function getA() of the pedigreemm package can be used to check the result

charlotte-ngs/lbgfs2021 documentation built on Dec. 19, 2021, 3:01 p.m.