ratioOverlap | R Documentation |
Calculate the proportion of the species' range (e.g., a thresholded SDM) that is contained by landcover categories taken from a shapefile. Example shapefile categories include protected areas, threatened areas. ratioOverlap returns a list of the masked raster layer and the percent of the total range that lies within the shapefile polygons specified. If shp is a raster representing an environmental layer, the proportion of presence within quantiles of the environmental layer and the correlation between the layer and the range are returned.
ratioOverlap(
r,
shp = NULL,
rasMask = NULL,
field = NULL,
category = NULL,
subfield = FALSE,
quant = "quartile"
)
r |
either categorical raster or shapefile object representing a binary range. |
shp |
either 1) a shapefile of land cover features or 2) a continuous raster. Must be in same projection as r parameter. If shp is a raster, then the number of cells within each quantile are calculated. |
rasMask |
(optional) a raster layer to calculate the Pearson correlation with the object r. Only if r or shp is a raster layer. |
field |
The shapefile field attribute containing the features to compare (i.e., the column name). |
category |
a list of the names of shapefile features to compare. If all features are to be used, input "All". |
subfield |
boolean. If TRUE, the overlap ratio of all unique categories of shp will be calculated. |
quant |
Either the character string "quartile" for the ratio of each quartile, or a concatenation of values to use instead. |
a list of three objects. The first object is a raster object showing the masked range. The second is a character showing the percentage of range within the category of interest. The third shows the correlation with rasMask if it is supplied.
# create binary raster
r <- raster::raster(nrows=108, ncols=108, xmn=-50, xmx=50)
raster::values(r)<- runif(n = (108*108))
r[r < 0.5] <- NA
r[r > 0.5] <- 1
# create shp
shp <- raster::raster(nrows=108, ncols=108, xmn=-50, xmx=50)
raster::values(shp)<- runif(n = (108*108))
# ratioOverlap
ratioOverlap(r = r, shp = shp)
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