| str_sub | R Documentation |
str_sub will recycle all arguments to be the same length as the
longest argument. If any arguments are of length 0, the output will be
a zero length character vector.
str_sub(string, start = 1L, end = 1000000L) str_sub(string, start = 1L, end = 1000000L, omit_na = FALSE) <- value
string |
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start |
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end |
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omit_na |
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value |
replacement |
Substrings are inclusive - they include the characters at both start and
end positions. str_sub(string, 1, -1) will return the complete
substring, from the first character to the last.
This function includes limited support for replacement form. Substring length
must match replacement length only one replacement can be made per string.
For multiple replacements per string it is probably better to use mgsub()
from the mgsub package.
Returns a character vector of substring(s) from start to end
(inclusive). Will be the length of longest input argument.
hw <- "Hadley Wickham"
str_sub(hw, 1, 6)
str_sub(hw, end = 6)
str_sub(hw, 8, 14)
str_sub(hw, 8)
str_sub(hw, c(1, 8), c(6, 14))
# Negative indices
str_sub(hw, -1)
str_sub(hw, -7)
str_sub(hw, end = -7)
# Alternatively, you can pass in a two column matrix, as in the
# output from str_locate_all
pos <- str_locate_all(hw, "[aeio]")[[1]]
str_sub(hw, pos)
str_sub(hw, pos[, 1], pos[, 2])
# Vectorisation
str_sub(hw, seq_len(nchar(hw)))
str_sub(hw, end = seq_len(nchar(hw)))
# Replacement form
# (Limited support, substring length must match replacement length and
# only one replacement can be made per string.)
test <- c("red", "orange", "green", "blue")
str_sub(test, 1, 3) <- "333"
test
test2 <- c("Africa", "Asia", "Australia")
str_sub(test2, -2) <- "z"
test2
# If you want to keep the original string if some argument is NA,
# use omit_na = TRUE
x1 <- x2 <- x3 <- x4 <- "AAA"
str_sub(x1, 1, NA) <- "B"
str_sub(x2, 1, 2) <- NA
str_sub(x3, 1, NA, omit_na = TRUE) <- "B"
str_sub(x4, 1, 2, omit_na = TRUE) <- NA
x1; x2; x3; x4
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