tools/rnblight/example_filt.md

In holgerbrandl/datautils: Small Utilities to make R-scripting more fun

Frequency tests

• Example: Prop of dieting woman higher than for men?

?fisher.test

Proportion Tests

prop.test(x=333, n=1022, conf.level=0.98)

prop.test(x=333, n=1022)

From http://stats.stackexchange.com/questions/60073/confidence-interval-for-difference-between-proportions

The sample size is 34, of which 19 are females and 15 are males. Therefore, the difference in proportions is 0.1176471.

19/34 - 15/34

prop.test(x=c(19,15), n=c(34,34), correct=FALSE)

## also works for single proportion
#prop.test(x=c(19), n=c(34), correct=FALSE)
#prop.test(x=c(19,15,20), n=c(34,34,34), correct=FALSE)

Also see http://stat.ethz.ch/R-manual/R-devel/library/stats/html/prop.test.html

Nice math introhttps://onlinecourses.science.psu.edu/statprogram/node/164 with t-statistc

Confidence around proportions

Formula:

If the samples size n and population proportion p satisfy the condition that np ≥ 5 and n(1 − p) ≥ 5, than the end points of the interval estimate at (1 − α) confidence level is defined in terms of the sample proportion as follows.

CI math is detailed out under http://www.statisticslectures.com/topics/ciproportions/

prop.test(x=333, n=1022, conf.level=0.98)

plot(1:10)
plot(1:10)

prop.test(x=333, n=1022)

plot(1:10)

holgerbrandl/datautils documentation built on Nov. 25, 2022, 4:43 a.m.