filename: Define a filename from current date
In lanzheng0728/chinaWeather: test package for weather

Define a filename from current date

1	filename(date = Sys.time())

date

input a date type

character a file name

1 2	filename() filename(as.Date("20120701",format="%Y%m%d"))

lanzheng0728/chinaWeather documentation built on May 20, 2019, 7:56 p.m.

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