Description Usage Arguments Value References
View source: R/greedy_knapsack.r
Knapsack Problem using the greedy approach
1 | greedy_knapsack(x, W)
|
x |
value |
W |
weight |
A list giving total no of objects and the maximum weight it can hold
x -knapsack_objects
W - total weight it can hold
'https://en.wikipedia.org/wiki/Knapsack_problem' order data decrasely by value(i)/weight(i) Problem: value(i)/weight(i) is equal but value(i) is not equal should order decreasely by value(i) too. print(new_data)
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