falsePosition: falsePosition
In ppcamp/r-edo-solver: Some mathematical algorithms used in numeric solutions

Description Usage Arguments Details Value Note See Also Examples

View source: R/main.r

Calculates root using false position method.

1	falsePosition(func, p0, p1, n0, tol, VERBOSE, VECTOR, DECIMAL)

`func`	STRING Derivative formula write in STRING. NOTE: observes that exponential values must use '**' instead operator '^'
`p0`	NUMBER Lower boundary
`p1`	NUMBER Upper boundary
`tol`	OPTIONAL NUMBER Tolerance, how close to 0 must be. NOTE: default value is 10⁻¹⁵
`n0`	NUMBER Maximum n0s to run. It will loop n0 times, however, if find root, will stop before.
`VERBOSE`	OPTIONAL BOOLEAN See results for each iteration
`VECTOR`	OPTIONAL BOOLEAN Return a Data frame with calculated values, instead of P, i.e., not show if 'Fail'.
`DECIMAL`	OPTIONAL NUMBER Pass a value to round variables. By default, is settled to 13

Depends of getFuncValue()

`DEFAULT`	FLOAT Possible solution for f(x) or 'Fail'.
`VECTOR=1`	DATA FRAME Iterations values, where i is equal to line row

How to see response for (i in 2:nrow(l))

cat( sprintf("%d\t %.9f\t %.9f\t %.9f\t %.9f", l[i,1],l[i,2],l[i,3],l[i,4],l[i,5]), sep='\n')

Numerical Analysis 9ed Burden

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falsePosition(func='cos(x)', p0=1, p1=2, n0=15)
falsePosition(func='x^3 + 4*x^2 - 10', p0=1, p1=2, n0=15, VERBOSE=1)
falsePosition(func='x^3 + 4*x^2 - 10', p0=1, p1=2, n0=15, VECTOR=1, DECIMAL=9)