list.order | R Documentation |
Give the order of each list element by expression
list.order(.data, ..., keep.names = FALSE, na.last = TRUE)
.data |
A |
... |
A group of lambda expressions |
keep.names |
Whether to keep the names of |
na.last |
The way to deal with |
an integer
vector.
list.sort
x <- list(p1 = list(type='A',score=list(c1=10,c2=8)), p2 = list(type='B',score=list(c1=9,c2=9)), p3 = list(type='B',score=list(c1=9,c2=7))) list.order(x, type, (score$c2)) # order by type (ascending) and score$c2 (descending) list.order(x, min(score$c1,score$c2)) list.order(x, min(score$c1,score$c2), keep.names=TRUE)
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