knitr::opts_chunk$set(echo = TRUE) options(digits=3) library(causl) library(survey)
We can also fit models in which some of the covariates and/or outcomes are binary. For example, suppose we assume that \begin{align} Z_1 &\sim N(0, \sigma_1^2) & Z_2 &\sim \text{Bernoulli}(p_2) & Y \mid do(X=x) \sim N(0, \sigma_y^2) \end{align} and $X \mid Z_1=z_1,Z_2=z_2 \sim \text{Bernoulli}(q)$, and we assume a Gaussian copula over $Z_1,Z_2,Y$ with correlation $R$, where $\rho_{Z_1Z_2} = 0.5$, $\rho_{Z_1Y} = 0.3$ and $\rho_{Z_2Y} = 0.4$.
Then we can set up this model in the usual way:
forms <- list(list(Z1 ~ 1, Z2 ~ 1), X ~ Z1*Z2, Y ~ X, ~ 1) fams <- list(c(1,5), 5, 1, 1) pars <- list(Z1 = list(beta=0, phi=1), Z2 = list(beta=0), X = list(beta=c(-0.3,0.1,0.2,0)), Y = list(beta=c(-0.25, 0.5), phi=0.5), cop = list(beta=matrix(c(0.5,0.3,0.4), nrow=1))) cm <- causl_model(formulas = forms, family = fams, pars = pars)
Now call rfrugal
as usual.
set.seed(1234) n <- 1e4 dat <- rfrugal(n, causl_model = cm)
Then we can check that the distributions follow the specification that we asked for.
ks.test(dat$Z1, pnorm) binom.test(sum(dat$Z2), n=n, p = 0.5) glmX <- glm(X ~ Z1*Z2, family=binomial, data=dat) summary(glmX)$coefficients
These are all consistent with the values we provided. We can finally check the outcome model.
ps <- predict(glmX, type="response") wt <- dat$X/ps + (1-dat$X)/(1-ps) glmY <- svyglm(Y ~ X, design = svydesign(~1, weights=wt, data=dat)) summary(glmY)$coefficients
We can also extend this to variables that are categorical or ordered
categorical. These options correspond to the family indicators 11 and 10
respectively, or they can be accessed by passing the strings "categorical"
and "ordinal"
to the family
argument. Both types of variable are stored as
a factor, with labels for the objects 1
, 2
, up to $\ell$, where $\ell$ is
the number of levels.
These methods respectively use a
contrast with the baseline level, or a contrast with the category immediately
below the current one in the ordering. For example, if we have a three variable
categorical variable using the formula Z ~ A
then the parameters are of the
form:
\begin{align}
\log \frac{P(Z=i)}{P(Z=1)} &= \beta_{0i} + \beta_{ai} a, & & i = 2,\ldots,\ell.
\end{align}
For a categorical variable the contrasts become $\log {P(Z=i)/P(Z=i-1)}$
for the same range of $i$.
The regression parameters can be passed either as a vector or a matrix, but in
either case they must be ordered so that all the coefficients for one contrast
precede all those for another. For example, if we want we could put
Z = list(beta = c(0.5,0.1,-0.5,0.4), nlevel = 3)
in the pars
argument to
require that
\begin{align}
\log \frac{P(Z=2)}{P(Z=1)} &= 0.5 + 0.1 a & \log \frac{P(Z=3)}{P(Z=1)} &= -0.5 + 0.4 a
\end{align}
for an unordered categorical variable, and the same for an ordinal variable but
replacing the second quantity with $\log {P(Z=3)/P(Z=2)}$. Equivalently, we
could put Z = list(beta = matrix(c(0.5,0.1,-0.5,0.4), nrow=2), nlevel = 3)
,
and the same model would be fitted.
forms <- list(list(Z0 ~ A0, Z1 ~ A0), list(A0 ~ 1, A1 ~ A0*Z0), Y ~ A0*A1, ~ A0) fams <- list(c("categorical","categorical"),c(5,5),1,1) pars <- list(A0 = list(beta = 0), Z0 = list(beta = c(0.3,-0.2,0.4,0.1), nlevel=3), Z1 = list(beta = c(0.3,-0.2,0.4,0.1), nlevel=3), A1 = list(beta = 2*c(-0.3,0.4,0.3,0.5,0.3,0.5)), Y = list(beta = c(-0.5,0.2,0.3,0), phi=1), cop = list(beta=c(2,0.5))) cm <- causl_model(formulas=forms, pars=pars, family=fams)
In this case we set both covariate variables to be categorical.
set.seed(123) n <- 5e4 dat <- rfrugal(n=n, causl_model=cm)
Now we can check that the parameters being simulated match those input.
glm(I(Z0==2) ~ A0, family=binomial, data=dat[dat$Z0 != 3,])$coefficients glm(I(Z0==3) ~ A0, family=binomial, data=dat[dat$Z0 != 2,])$coefficients glm(I(Z1==2) ~ A0, family=binomial, data=dat[dat$Z1 != 3,])$coefficients glm(I(Z1==3) ~ A0, family=binomial, data=dat[dat$Z1 != 2,])$coefficients
Finally, we can check that the outcome model works as it should.
ps <- predict(glm(A1 ~ A0*Z0, family=binomial, data=dat), type="response") wt <- dat$A1/ps + (1-dat$A1)/(1-ps) summary(svyglm(Y ~ A0*A1, design = svydesign(~1,data=dat,weights=wt)))$coef
Comparing with a naïve (unweighted) estimate.
summary(svyglm(Y ~ A0*A1, design = svydesign(~1,data=dat,weights=~1)))$coef
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