dirdf: List Files in a Directory as a Data Frame

In ropenscilabs/dirdf: Extracts Metadata from Directory and File Names

Description

Creates a data frame using information from paths and file names. It searches through the directories in order to create the path names of the files. It accepts either a template or a regular expression and column names.

Usage

dirdf(paths, template = NULL, regexp = NULL, colnames = NULL,
  missing = NA_character_, recursive = TRUE, ...)

dirdf2(paths, template = NULL, regexp = NULL, colnames = NULL,
  missing = NA_character_, recursive = TRUE, ...)

Arguments

paths	character vector with zero or more paths that will be searched.
template	template character string, e.g. "Country/Province/City/StationID_Date.ext".
regexp	regular expression used to parse the file names. Only one of the arguments regexp and template must be specified, i.e. only one of them can be non-NULL.
colnames	character vector containing the names of the columns in the data frame. Not required if using template or if regexp uses named capturing groups (see examples), but may still be used to override column names.
missing	value to use for unmatched optional template elements or regexp capturing groups.
recursive	if TRUE, it will recursively search over directories.
...	Additional arguments pass to base::dir().

See Also

dirdf_parse()

Examples

path1 <- system.file(package = "dirdf", "examples", "dataset_1")
template1 <- "Year-Month-Day_Assay_Plasmid-Type-Fraction_WellNumber?.extension"
files1 <- dirdf(path1, template = template1)
print(files1)

path2 <- system.file(package = "dirdf", "examples", "dataset_2")
template2 <- "Date_Assay_Experiment_WellNumber?.extension"
files2 <- dirdf(path2, template = template2)
print(files2)

ropenscilabs/dirdf documentation built on May 27, 2019, 8:32 p.m.