get_node.Tree: Get a 'Node' using it's name from a 'Tree'

Description Usage Arguments

Description

Get a ‘Node' using it’s name from a 'Tree'

Usage

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## S3 method for class 'Tree'
get_node(x, node_name, ...)

Arguments

x

A 'Tree'.

node_name

The name of a 'Node' within the 'Tree'.

...

Other arguments: unused at present.


russHyde/s3tree documentation built on May 16, 2019, 5:03 a.m.