hadam_mo_cpp | R Documentation |
Computation of Maximal-Overlap Hadamard Variance
avar_mo_cpp(x)
x |
A |
Given N equally spaced samples with averaging time tau = n*tau_0, where n is an integer such that 1<= n <= N/2. Therefore, n is able to be selected from {n|n< floor(log2(N))} Then, M = N - 2n samples exist. The Maximal-overlap estimator is given by: \frac{1}{{2≤ft( {N - 2k + 1} \right)}}∑\limits_{t = 2k}^N {{{≤ft[ {{{\bar Y}_t}≤ft( k \right) - {{\bar Y}_{t - k}}≤ft( k \right)} \right]}^2}}
where {{\bar y}_t}≤ft( τ \right) = \frac{1}{τ }∑\limits_{i = 0}^{τ - 1} {{{\bar y}_{t - i}}} .
av A list
that contains:
"clusters"The size of the cluster
"hadamard"The Hadamard variance
"errors"The error associated with the variance estimation.
JJB
Long-Memory Processes, the Allan Variance and Wavelets, D. B. Percival and P. Guttorp
set.seed(999) # Simulate white noise (P 1) with sigma^2 = 4 N = 100000 white.noise = rnorm(N, 0, 2) #plot(white.noise,ylab="Simulated white noise process",xlab="Time",type="o") #Simulate random walk (P 4) random.walk = cumsum(0.1*rnorm(N, 0, 2)) combined.ts = white.noise+random.walk av_mat = avar_mo_cpp(combined.ts)
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