log1mexp: Compute f(a) = log(1 +/- exp(-a)) Numerically Optimally
In sparktseung/LRMoE: Logit-Weighted Reduced Mixture-of-Experts
log1mexp R Documentation
Compute f(a) = log(1 +/- exp(-a)) Numerically Optimally
Description
Compute f(a) = log(1 +/- exp(-a)) Numerically Optimally
This helper function was a directly copy from copula package. It was initialized here intend to maintain the minimum package complexity
Usage
log1mexp(a, cutoff = log(2))
Arguments
a
numeric vector of positive values
cutoff
log(2) is “optimal”, but the exact value is unimportant, and anything in (0.5, 1) is fine.
sparktseung/LRMoE documentation built on March 21, 2022, 3:22 a.m.
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| log1mexp | R Documentation |
Compute f(a) = log(1 +/- exp(-a)) Numerically Optimally
Description
Compute f(a) = log(1 +/- exp(-a)) Numerically Optimally
This helper function was a directly copy from copula package. It was initialized here intend to maintain the minimum package complexity
Usage
log1mexp(a, cutoff = log(2))
Arguments
a |
|
cutoff |
|
R Package Documentation
Browse R Packages
We want your feedback!
Note that we can't provide technical support on individual packages. You should contact the package authors for that.
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