#' This function calculates the molar concentration of something
#' please provide:
#' 1. volume of the used substance (microliters) of interest that was dissolved in
#' 2. volume of the medium in which the substance was dissolved
#' 3. molar weight of the substance of interest
#' 4. Percentage of the substance of interest expressed as a fraction (0.37 for a 37% acid)
#' 5. substance density - rho expressed in grams per 1000000 microliteres (1 liter)
#' You will get the value of molar concentration of the calculated medium expressed in mols per liter
#' @export solution.molarity
solution.molarity <- function(substance_vol,medium_vol,molar_weight,solution_percent,substance_rho){
#acid_vol = 10 #this is how mach microliters I took into the broth
sample_vol = substance_vol+medium_vol # this is how big is the sample plus acid
# molar_weight = 74.07854 # this is the molar weight of the propionic acid
# solution_percent = 0.5 # this is the solution I prepared in the beginning
# acid_rho= 990/1000000# the grams per liter in microliter
substance_grams = substance_vol*solution_percent*substance_rho # this is how much the pure acid weights in the final solution
substance_mols = substance_grams/molar_weight # this is how many mols is in this weight
solution_molar = (substance_mols*1000000)/sample_vol # this is how molar the broth solution is
return(solution_molar)
}
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