knitr::opts_chunk$set( collapse = TRUE, comment = "#>", fig.width = 7, fig.height = 4, fig.align = "center" )
A fitted choice model answers questions about choice probabilities: which of
two train trips a traveler is likely to book, how the support for a
wind-power project changes with the compensation, and how well the model
predicts the choices of deciders that were not used for estimation. In the
probit model introduced in the vignette Get started with RprobitB,
the choice probability of an alternative is the probability that its latent
utility exceeds the utilities of the other alternatives, and it depends on
the covariates of the occasion and on the parameters. predict() evaluates
these probabilities under every retained posterior draw and averages them,
so that the predictions account for the posterior uncertainty about the
parameters [@Gelman1996]. This vignette covers predictions for the
population and for individual deciders, scenarios, out-of-sample
prediction, residuals, and marginal effects. The examples use data sets of
the mlogit package [@Croissant2020], the choicedata package
[@Oelschlaeger2026a], and the MASS package [@VenablesRipley2002].
library(RprobitB) set.seed(1)
The Train data of the mlogit package contain about a dozen choices by
each of 235 Dutch travelers between two hypothetical train trips that differ
in price, travel time, number of changes, and comfort class [@BenAkiva1993].
As in the vignette Get started with RprobitB, the prices are converted
to euro and the travel times to hours. That vignette fits one price
coefficient for all travelers. Here the price coefficient is a normal random
effect, as introduced in the vignette
Modeling preference heterogeneity: every traveler has an individual
price coefficient, drawn from a normal population distribution whose mean
and variance are estimated. The fit uses the first 100 travelers. The
individual draws are saved because the conditional predictions below use
them, and thinning keeps 100 draws in total, which keeps the predictions
fast.
data("Train", package = "mlogit") Train$price_A <- Train$price_A / 100 / 2.20371 Train$price_B <- Train$price_B / 100 / 2.20371 Train$time_A <- Train$time_A / 60 Train$time_B <- Train$time_B / 60 train_small <- Train[Train$id %in% unique(Train$id)[1:100], ] model <- fit( choice ~ price + time + change + factor(comfort) | 0, data = train_small, random_effects = "price", column_decider = "id", column_occasion = "choiceid", iterations = 1500, warmup = 750, thin = 15, chains = 2, save_individual_draws = TRUE, progress = FALSE ) summary(model)
mu[price] and Omega[price,price] are the mean and the variance of the
price coefficient across the population. Price sensitivity differs
considerably between travelers, which the predictions below take into
account.
By default, predict() returns one row per choice occasion with the
identifiers, the most probable alternative in .prediction, and the
posterior mean probability of every alternative. These population
predictions integrate over the estimated population distribution of the
random coefficient, so they apply to any traveler from the population.
population <- predict(model) head(population)
uncertainty = TRUE adds the posterior standard deviation and an
equal-tailed credible interval of every probability, here at the 90% level.
The intervals reflect the posterior uncertainty about the parameters.
head(predict(model, uncertainty = TRUE, level = 0.9))
The dozen choices of a traveler are informative about their individual
price coefficient. coef(level = "individual") returns the posterior mean
of every traveler's coefficient, and predict(type = "conditional") uses
the individual draws instead of the population distribution. Conditional
predictions exist only for the deciders in the fitted data, and they are
usually sharper because they use the decider's own choices. This partial
pooling is the main argument for hierarchical Bayesian choice models
[@Allenby1998; @Huber2001].
head(coef(model, level = "individual")) conditional <- predict(model, type = "conditional") head(conditional)
The hit rate, the share of correctly predicted choices in the fitted data, is one measure of the gain:
observed <- model.frame(model)$choice c( population = mean(population$.prediction == observed, na.rm = TRUE), conditional = mean(conditional$.prediction == observed, na.rm = TRUE) )
The hit rate evaluates the
predictions at a single threshold, a probability of one half. An ROC curve
compares them at every threshold: as the threshold for predicting trip B
decreases from one to zero, the curve plots the share of B choices
predicted correctly against the share of A choices wrongly predicted as
B. The plotROC package [@Sachs2017] draws the curves with ggplot2
[@Wickham2016].
library(ggplot2) library(plotROC) roc_data <- rbind( data.frame( prediction = "population", chose_B = as.integer(observed == "B"), probability = population$probability_B ), data.frame( prediction = "conditional", chose_B = as.integer(observed == "B"), probability = conditional$probability_B ) ) roc_data$prediction <- factor( roc_data$prediction, levels = c("population", "conditional") ) roc_plot <- ggplot( roc_data, aes(d = chose_B, m = probability, color = prediction) ) + geom_roc(n.cuts = 0) + style_roc() roc_plot
The conditional curve lies above the population curve and therefore has the larger area under the curve, which equals one for a perfect and one half for an uninformative prediction.
A scenario predicts the choice probabilities for modified attributes. Near
Setskog in Norway, 308
residents were asked six times to choose between two plans for a proposed
wind-power project and the status quo without the project, alternative 1
[@Dugstad2024]. The plans varied the number and height of the turbines, the
routing of the power line, and an annual reduction in municipal taxes
offered as compensation. The study also measured each respondent's
collective psychological ownership of the affected area, a standardized
score of how strongly they feel that the landscape belongs to the residents.
The score does not vary across alternatives and therefore enters the second
part of the formula, which gives it one coefficient per plan relative to the
status quo. The fit uses the first 150 respondents.
wind_formula <- choice ~ turbines + height + powerline + compensation | psychological_ownership
data("wind_power_choice", package = "choicedata") respondents <- unique(wind_power_choice$respondent)[1:150] wind_small <- wind_power_choice[ wind_power_choice$respondent %in% respondents, ] wind <- fit( formula = wind_formula, data = wind_small, column_decider = "respondent", column_occasion = "occasion", iterations = 10000, warmup = 5000, thin = 10, chains = 1, progress = FALSE ) coef(wind)[c("beta[compensation]", "beta[psychological_ownership_2]")]
The compensation coefficient is positive and the ownership coefficient negative: compensation makes a plan more attractive, and residents with a stronger feeling of ownership are less willing to leave the status quo.
What would happen if the municipality doubled the compensation?
newdata accepts a data frame in the layout of the fitted data, with or
without the response column. The scenario below doubles the compensation of
both plans in the first four choice tasks and compares the probability of
the status quo before and after.
tasks <- model.frame(wind)[1:4, ] tasks$choice <- NULL scenario <- tasks scenario$compensation_2 <- 2 * scenario$compensation_2 scenario$compensation_3 <- 2 * scenario$compensation_3 cbind( before = predict(wind, newdata = tasks)$probability_1, after = predict(wind, newdata = scenario)$probability_1 )
Doubling the compensation lowers the probability of the status quo in all four tasks.
Predictive performance is best judged on deciders that were not used for
estimation [@Vehtari2017]. In an arena tournament on the chess server
Lichess, a player may go Berserk at the start of a game: the clock is
halved, and a win earns one extra tournament point. Players on a winning
streak collect double points, so a loss is more costly for them. The
lichess_berserk_choice data of the choicedata package record this
decision for 5852 players in the Lichess Yearly Rapid Arena of April 2026,
game by game, together with the playing color, the player's rating, the
rating difference to the opponent, the remaining tournament time, and
whether the player was on a streak. All covariates describe the game and
are constant across the two alternatives, so they enter the second part of
the formula, which gives each of them one coefficient for the alternative
TRUE relative to FALSE, for example beta[rating_TRUE]. Logical
covariates appear as dummy variables such as streakTRUE.
berserk_formula <- berserk ~ 0 | white + rating + ratingDifference + minutesRemaining + streak
The fit uses the games of the first 300 players. train_test() splits them by
decider: test_number = 60 puts all games of 60 players into the test set and
the games of the other players into the training set.
data("lichess_berserk_choice", package = "choicedata") players <- unique(lichess_berserk_choice$deciderID) first_players <- lichess_berserk_choice$deciderID %in% players[1:300] split <- train_test(lichess_berserk_choice[first_players, ], test_number = 60) berserk <- fit( formula = berserk_formula, data = split$train, column_occasion = "occasionID", iterations = 1000, warmup = 500, chains = 2, progress = FALSE ) coef(berserk)
The rating coefficient is positive: stronger players go Berserk more often.
The coefficients of the streak and of the remaining time are negative. How well
does the model predict the games of the 60
players in the test set? newdata takes the test set as it is, and the
predicted alternative is compared with the observed one.
holdout_prediction <- predict(berserk, newdata = split$test) holdout_choice <- as.character(split$test$berserk) c( accuracy = mean(holdout_prediction$.prediction == holdout_choice), share_berserk = mean(split$test$berserk) )
The hit rate is only slightly higher than the share of games without Berserk, which the rule that never predicts Berserk would already reach, so the hit rate alone is a weak criterion for an unbalanced binary response. A calibration analysis assesses the predicted probabilities instead. It groups the hold-out games by predicted Berserk probability in intervals of width 0.1 and compares the mean predicted probability with the observed Berserk rate in each group; groups with fewer than 50 games are dropped.
predicted <- holdout_prediction$probability_TRUE bins <- cut(predicted, breaks = seq(0, 1, by = 0.1)) calibration <- data.frame( games = as.vector(table(bins)), predicted = as.vector(tapply(predicted, bins, mean)), observed = as.vector(tapply(split$test$berserk, bins, mean)), row.names = levels(bins) ) large <- calibration[calibration$games >= 50, ] round(large, 2)
The calibration plot shows the same table. Points on the diagonal mean that the predicted probability equals the observed rate, and the point sizes are proportional to the number of games in a group.
plot( large$predicted, large$observed, xlim = c(0, 1), ylim = c(0, 1), pch = 19, cex = 0.5 + 2 * large$games / max(large$games), xlab = "predicted Berserk probability", ylab = "observed Berserk rate" ) abline(0, 1, lwd = 2, col = "grey50")
The observed Berserk rate rises with the predicted probability, so the model orders the games by their Berserk rate. In the group with the highest predictions, the observed rate exceeds the predicted probability, so the model underpredicts Berserk for these games.
residuals() returns the observed choice indicators minus the posterior
mean probabilities, one row per choice occasion and one column per
alternative. The rows of observed occasions sum to zero, and occasions with
a missing response yield NA. A single residual is uninformative, because
the indicator is zero or one while the probability lies in between, so the
residuals are averaged over groups of occasions. The average residual per
traveler shows whose choices the model reproduces:
model_residuals <- residuals(model) head(model_residuals) by_decider <- tapply( model_residuals[, "A"], model.frame(model)$id, mean, na.rm = TRUE ) round(quantile(by_decider, c(0, 0.25, 0.5, 0.75, 1)), 3)
Most travelers have an average residual close to zero. For the travelers at
the extremes, the model predicts trip A too often or too rarely across all
their questions.
Grouping by a covariate checks the functional form instead, here by the
price of trip A in four groups of equal size:
price_group <- cut( model.frame(model)$price_A, breaks = quantile(model.frame(model)$price_A, seq(0, 1, 0.25)), include.lowest = TRUE ) round(tapply(model_residuals[, "A"], price_group, mean, na.rm = TRUE), 3)
All four group averages are close to zero. A systematic pattern, for example positive residuals at both ends, would indicate a nonlinear price effect or an unmodeled preference class.
How much does one euro more change the probability of booking a trip? The
coefficients do not answer this directly, because the probit link is
nonlinear: the same change of a covariate moves the probability most where
the alternatives are close in utility and little where one alternative
dominates. interpret() therefore differentiates the predicted
probabilities numerically. type = "mea" evaluates the derivative for one
occasion whose covariates equal the observed averages, reported in the
column at. type = "ame" evaluates the derivative for every observed
occasion and averages, which weights the occasions as they occur in the data.
Both use every posterior draw and
therefore come with credible intervals.
interpret(model, type = "mea") average_effects <- interpret(model, type = "ame") average_effects
Averaged over the observed occasions, one euro more
lowers the probability of a trip by about
r round(-100 * average_effects$mean[average_effects$covariate == "price"][1])
percentage points and one hour more by about
r round(-100 * average_effects$mean[average_effects$covariate == "time"][1])
percentage points.
The at argument replaces the averages of selected
covariates. A much cheaper trip B moves its probability close to one,
where one euro more changes it only marginally:
interpret(model, type = "mea", at = c(price_A = 30, price_B = 10))
An ordered model compares one latent utility per occasion with increasing
thresholds that partition it into the levels of the response, as the
vignette Model specification and variants describes. For such a
model, predict() returns the probability of every level. The smoking model
of that vignette predicts how often a student smokes from their age and
exercise habits.
data("survey", package = "MASS") smoking <- fit( Smoke ~ Age + Exer | 0, data = survey, alternatives = c("Never", "Occas", "Regul", "Heavy"), choice_type = "ordered", column_decider = NULL, chains = 1 ) head(predict(smoking))
Every row has four probabilities that sum to one, and .prediction names
the most probable level. Because most students never smoke, this level is
the most probable for almost every student, and the probabilities are more
informative than the predicted level. A
scenario works as before. Ten more years of age shift the probability of
never smoking of the first three students:
students <- model.frame(smoking)[1:3, ] students$Smoke <- NULL older <- students older$Age <- older$Age + 10 cbind( before = predict(smoking, newdata = students)$probability_Never, after = predict(smoking, newdata = older)$probability_Never )
The probability rises for all three students, in the direction implied by the negative age coefficient.
Predictions describe what a model expects, not whether it is better than another model. That comparison is the subject of the vignette Bayesian model evaluation.
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