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#' Calculate risks from arctanh RD and log OP
#'
#' @param atanhrd arctanh of risk difference
#'
#' @param logop log of odds product
#'
#' @details The \eqn{log OP} is defined as \eqn{log OP = log[(P(y=1|x=0)/P(y=0|x=0))*(P(y=1|x=1)/P(y=0|x=1))]}.
#' The inverse hyperbolic tangent function \code{arctanh} is defined as \eqn{arctanh(z) = [log(1+z) - log(1-z)] / 2}.
#'
#' @return a vector \eqn{(P(y=1|x=0),P(y=1|x=1))}
#'
#' @examples getProbScalarRD(0,0)
#'
#' set.seed(0)
#' logrr = rnorm(10,0,1)
#' logop = rnorm(10,0,1)
#' probs = mapply(getProbScalarRD, logrr, logop)
#' rownames(probs) = c("P(y=1|x=0)","P(y=1|x=1)")
#' probs
#'
#' @export
getProbScalarRD = function(atanhrd, logop) {
if(length(atanhrd) == 2){
logop = atanhrd[2]
atanhrd = atanhrd[1]
}
if (logop > 350) {
if (atanhrd < 0) {
p0 = 1
p1 = p0 + tanh(atanhrd)
} else {
p1 = 1
p0 = p1 - tanh(atanhrd)
}
} else {
## not on boundary logop = 0; solving linear equations
if (same(logop, 0)) {
p0 = 0.5 * (1 - tanh(atanhrd))
} else {
p0 = (-(exp(logop) * (tanh(atanhrd) - 2) - tanh(atanhrd)) - sqrt((exp(logop) *
(tanh(atanhrd) - 2) - tanh(atanhrd))^2 + 4 * exp(logop) *
(1 - tanh(atanhrd)) * (1 - exp(logop))))/(2 * (exp(logop) -
1))
}
p1 = p0 + tanh(atanhrd)
}
return(c(p0, p1))
}
#' Calculate risks from arctanh RD and log OP (vectorised)
#'
#' @param atanhrd arctanh of risk difference
#'
#' @param logop log of odds product
#'
#' @details The \eqn{log OP} is defined as \eqn{log OP = log[(P(y=1|x=0)/P(y=0|x=0))*(P(y=1|x=1)/P(y=0|x=1))]}.
#' The inverse hyperbolic tangent function \code{arctanh} is defined as \eqn{arctanh(z) = [log(1+z) - log(1-z)] / 2}.
#'
#' @return a matrix \eqn{(P(y=1|x=0),P(y=1|x=1))} with two columns
#'
#' @examples getProbRD(0,0)
#'
#' set.seed(0)
#' logrr = rnorm(10,0,1)
#' logop = rnorm(10,0,1)
#' probs = getProbRD(logrr, logop)
#' colnames(probs) = c("P(y=1|x=0)","P(y=1|x=1)")
#' probs
#'
#' @export
getProbRD = function(atanhrd, logop) {
if(is.matrix(atanhrd) && ncol(atanhrd) == 2){
logop = atanhrd[,2]
atanhrd = atanhrd[,1]
} else if(length(logop)==1 && is.na(logop) && length(atanhrd) == 2){
logop = atanhrd[2]
atanhrd = atanhrd[1]
}
p0 <- ifelse (logop > 350,
ifelse(atanhrd < 0,
1,
1 - tanh(atanhrd)),
## not on boundary logop = 0; solving linear equations
ifelse(same(logop, 0),
0.5 * (1 - tanh(atanhrd)),
(-(exp(logop) * (tanh(atanhrd) - 2) - tanh(atanhrd)) - sqrt((exp(logop) * (tanh(atanhrd) - 2) - tanh(atanhrd))^2 + 4 * exp(logop) * (1 - tanh(atanhrd)) * (1 - exp(logop))))/(2 * (exp(logop) - 1))))
p1 <- ifelse (logop > 350,
ifelse(atanhrd < 0,
1 + tanh(atanhrd),
1),
## not on boundary logop = 0
p0 + tanh(atanhrd))
cbind(p0,p1)
}
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