ex_vdpol: van der Pol Equation, Nonlinear Vacuum Tube Circuit, ODE

Description Usage Arguments Details Value Note Author(s) References Examples

Description

Problem originating from electronics, describing the behavior of nonlinear vacuum tube circuots.

It is an ODE, 2 equations.

Usage

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vdpol  (times = 0:2000, yini = NULL,  
        parms = list(), printmescd = TRUE,
        atol = 1e-6, rtol = 1e-6, ...)

Arguments

yini

the initial (state) values for the DE system. If y has a name attribute, the names will be used to label the output matrix.

times

time sequence for which output is wanted; the first value of times must be the initial time.

parms

list of parameters that overrule the default parameter values

atol

absolute error tolerance, either a scalar or a vector, one value for each y.

rtol

relative error tolerance, either a scalar or a vector, one value for each y,

printmescd

if TRUE the mixed error significant digits computed using the reference solution at time 5 are printed

...

additional arguments passed to the solver .

Details

The default parameters are: mu=1000

The default initial conditions are: y1 = 2, y2 = 0

Value

A matrix of class deSolve with up to as many rows as elements in times and as many columns as elements in yini, plus an additional column (the first) for the time value.

There will be one row for each element in times unless the solver returns with an unrecoverable error. If yini has a names attribute, it will be used to label the columns of the output value.

Note

This model is implemented in R

Author(s)

Karline Soetaert <[email protected]>

Francesca Mazzia <[email protected]>

References

http://www.dm.uniba.it/~testset

Examples

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out <- vdpol()
plot(out, lwd = 2, which = 1)

# compare to reference solution
out[nrow(out),-1] - reference("vdpol")

deTestSet documentation built on May 29, 2017, 2:56 p.m.