# fancycut: Like 'cut', turn a vector of numbers into a factor In fancycut: A Fancy Version of 'base::cut'

## Description

Like `cut`, turn a vector of numbers into a factor

## Usage

 ```1 2``` ```fancycut(x, na.bucket = NA, unmatched.bucket = NA, out.as.factor = TRUE, ...) ```

## Arguments

 `x` a numeric vector `na.bucket` what level should NA values be given? `unmatched.bucket` what level should numbers not covered by an interval be given? `out.as.factor` default is TRUE Should the resulting vector be a factor? If FALSE will return a character vector. `...` These take the form `tag = value`. Tags become the bucket names and values the interval definitions.

## Examples

 ``` 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30``` ```fancycut( x = -10:10, Zero = 0, Small = '[0,2)', Medium = '[2,5]', Large = '(5,10]' ) # The following examples are from Richie Cotton via # https://www.rdocumentation.org/packages/fancycut/versions/0.1.1/topics/fancycut # The tag = value syntax is useful. x <- seq.int(0, 1, 0.25) fancycut(x, low = '[0, 0.5]', high = '(0.5, 1]') # Not all the values have to live in a bucket. x <- seq.int(0, 1, 0.25) fancycut(x, low = '(0.2, 0.3]', high = '(0.7, 0.8)') # You can use unmatched.bucket to deal with these other intervals. x <- seq.int(0, 1, 0.25) fancycut(x, low = '(0.2, 0.3]', high = '(0.7, 0.8)', unmatched.bucket = 'other') # To match a specific value, make the lower and upper bound the same number. x <- seq.int(0, 1, 0.25) fancycut(x, low = '[0, 0.5)', half = '[0.5,0.5]', high = '(0.5, 1]') # To match NA values, use na.bucket. x2 <- c(seq.int(0, 1, 0.25), NA) fancycut(x2, low = '[0, 0.5)', high = '[0.5, 1]', na.bucket = 'missing') ```

fancycut documentation built on May 2, 2019, 5:56 a.m.