# wafflecut: Like 'cut', turn a vector of numbers into a factor In fancycut: A Fancy Version of 'base::cut'

## Description

Like cut, turn a vector of numbers into a factor

## Usage

 1 2 wafflecut(x, intervals, buckets = intervals, na.bucket = NA, unmatched.bucket = NA, out.as.factor = TRUE)

## Arguments

 x a numeric vector intervals a character vector of intervals buckets a character vector of levels for the new factor these have a 1-1 correspondence with intervals na.bucket what level should NA values be given? unmatched.bucket what level should numbers not covered by an interval be given? out.as.factor default is TRUE Should the resulting vector be a factor? If FALSE will return a character vector.

## Examples

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 wafflecut(-10:10, c('[0,2)','[2,5)','[5,10]'), c('Small','Medium','Large')) wafflecut(-10:10, c('[0,0]','(0,2]','(2,5)','[5,10]'), c('Zero','Small','Medium','Large')) wafflecut(-10:10, c('[0,2)','[2,5)','[5,10]'), c('Small','Medium','Large')) wafflecut(-10:10, c('[0,0]','[0,2]','(2,5)','[5,10]'), c('Zero','Small','Medium','Large')) # The following examples are from Richie Cotton via # https://www.rdocumentation.org/packages/fancycut/versions/0.1.1/topics/fancycut # Not all the values have to live in a bucket. x <- seq.int(0, 1, 0.25) wafflecut(x, c('(0.2, 0.3)', '(0.7, 0.8)'), c('low', 'high')) # You can use unmatched.bucket to deal with these other intervals. x <- seq.int(0, 1, 0.25) wafflecut(x, c('(0.2, 0.3)', '(0.7, 0.8)'), c('low', 'high'), unmatched.bucket = 'other') # To match NA values, use na.bucket. x2 <- c(seq.int(0, 1, 0.25), NA) wafflecut(x2, c('[0, 0.5)', '[0.5, 1]'), c('low', 'high'), na.bucket = 'missing')

fancycut documentation built on May 2, 2019, 5:56 a.m.