wafflecut: Like 'cut', turn a vector of numbers into a factor

In fancycut: A Fancy Version of 'base::cut'

Description

Like cut, turn a vector of numbers into a factor

Usage

wafflecut(x, intervals, buckets = intervals, na.bucket = NA,
  unmatched.bucket = NA, out.as.factor = TRUE)

Arguments

x	a numeric vector
intervals	a character vector of intervals
buckets	a character vector of levels for the new factor these have a 1-1 correspondence with intervals
na.bucket	what level should NA values be given?
unmatched.bucket	what level should numbers not covered by an interval be given?
out.as.factor	default is TRUE Should the resulting vector be a factor? If FALSE will return a character vector.

Examples

wafflecut(-10:10, c('[0,2)','[2,5)','[5,10]'), c('Small','Medium','Large'))

wafflecut(-10:10, c('[0,0]','(0,2]','(2,5)','[5,10]'), c('Zero','Small','Medium','Large'))

wafflecut(-10:10, c('[0,2)','[2,5)','[5,10]'), c('Small','Medium','Large'))

wafflecut(-10:10, c('[0,0]','[0,2]','(2,5)','[5,10]'), c('Zero','Small','Medium','Large'))


# The following examples are from Richie Cotton via
# https://www.rdocumentation.org/packages/fancycut/versions/0.1.1/topics/fancycut

# Not all the values have to live in a bucket.
x <- seq.int(0, 1, 0.25)
wafflecut(x, c('(0.2, 0.3)', '(0.7, 0.8)'), c('low', 'high'))

# You can use unmatched.bucket to deal with these other intervals.
x <- seq.int(0, 1, 0.25)
wafflecut(x, c('(0.2, 0.3)', '(0.7, 0.8)'), c('low', 'high'), unmatched.bucket = 'other')

# To match NA values, use na.bucket.
x2 <- c(seq.int(0, 1, 0.25), NA)
wafflecut(x2, c('[0, 0.5)', '[0.5, 1]'), c('low', 'high'), na.bucket = 'missing')

fancycut documentation built on May 2, 2019, 5:56 a.m.