ts_compare_data: Compare data over time periods

View source: R/ts-compare-data.R

ts_compare_dataR Documentation

Compare data over time periods

Description

Given a tibble/data.frame, you can get date from two different but comparative date ranges. Lets say you want to compare visits in one year to visits from 2 years before without also seeing the previous 1 year. You can do that with this function.

Usage

ts_compare_data(.data, .date_col, .start_date, .end_date, .periods_back)

Arguments

.data

The date.frame/tibble that holds the data

.date_col

The column with the date value

.start_date

The start of the period you want to analyze

.end_date

The end of the period you want to analyze

.periods_back

How long ago do you want to compare data too. Time units are collapsed using lubridate::floor_date(). The value can be:

  • second

  • minute

  • hour

  • day

  • week

  • month

  • bimonth

  • quarter

  • season

  • halfyear

  • year

Arbitrary unique English abbreviations as in the lubridate::period() constructor are allowed.

Details

  • Uses the timetk::filter_by_time() function in order to filter the date column.

  • Uses the timetk::subtract_time() function to subtract time from the start date.

Value

A tibble.

Author(s)

Steven P. Sanderson II, MPH

See Also

Other Time_Filtering: ts_time_event_analysis_tbl()

Examples

suppressPackageStartupMessages(library(dplyr))
suppressPackageStartupMessages(library(timetk))

data_tbl <- ts_to_tbl(AirPassengers) %>%
  select(-index)

ts_compare_data(
  .data           = data_tbl
  , .date_col     = date_col
  , .start_date   = "1955-01-01"
  , .end_date     = "1955-12-31"
  , .periods_back = "2 years"
  ) %>%
  summarise_by_time(
    .date_var = date_col
    , .by     = "year"
    , visits  = sum(value)
  )


healthyR.ts documentation built on Nov. 15, 2023, 9:07 a.m.