View source: R/kernel_functions.R
Kendall | R Documentation |
‘Kendall()' computes the Kendall’s tau, which happens to be a kernel function for ordinal variables, ranks or permutations.
Kendall(X, NA.as.0 = TRUE, samples.in.rows = FALSE, comp = "mean")
X |
When evaluating a single ordinal feature, X should be a numeric matrix or data.frame. If data is multivariate, X should be a list, and each ordinal/ranking feature should be placed in a different element of the list (see Examples). |
NA.as.0 |
Should NAs be converted to 0s? (Defaults: TRUE). |
samples.in.rows |
If TRUE, the samples are considered to be in the rows. Otherwise, it is assumed that they are in the columns. (Defaults: FALSE). |
comp |
If X is a list, this argument indicates how the ordinal/ranking variables are combined. Options are: "mean" and "sum". (Defaults: "mean"). |
Kernel matrix (dimension: NxN).
Jiao, Y. and Vert, J.P. The Kendall and Mallows kernels for permutations. International Conference on Machine Learning. PMLR, 2015. Link
# 3 people are given a list of 10 colors. They rank them from most (1) to least
# (10) favorite
color_list <- c("black","blue","green","grey","lightblue","orange","purple",
"red","white","yellow")
survey1 <- 1:10
survey2 <- 10:1
survey3 <- sample(10)
color <- cbind(survey1,survey2,survey3) # Samples in columns
rownames(color) <- color_list
Kendall(color)
# The same 3 people are asked the number of times they ate 5 different kinds of
# food during the last month:
food <- matrix(c(10, 1,18, 25,30, 7, 5,20, 5, 12, 7,20, 20, 3,22),ncol=5,nrow=3)
rownames(food) <- colnames(color)
colnames(food) <- c("spinach", "chicken", "beef" , "salad","lentils")
# (we can observe that, for person 2, vegetables << meat, while for person 3
# is the other way around)
Kendall(food,samples.in.rows=TRUE)
# We can combine this results:
dataset <- list(color=color,food=t(food)) #All samples in columns
Kendall(dataset)
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