| familycheck | R Documentation | 
Given a family id vector, also compute the familial grouping from first principles using the parenting data, and compare the results.
familycheck(famid, id, father.id, mother.id, newfam)
famid | 
 a vector of family identifiers  | 
id | 
 a vector of unique subject identifiers  | 
father.id | 
 vector containing the id of the biological father  | 
mother.id | 
 vector containing the id of the biological mother  | 
newfam | 
 the result of a call to   | 
The makefamid function is used to create a
de novo family id from the parentage data, and this is compared to the
family id given in the data.
a data frame with one row for each unique family id in the
famid argument.
Components of the output are
famid | 
 the family id, as entered into the data set  | 
n | 
 number of subjects in the family  | 
unrelated | 
 number of them that appear to be unrelated to anyone else in the entire pedigree set. This is usually marry-ins with no children (in the pedigree), and if so are not a problem.  | 
split | 
 number of unique "new" family ids. If this is 0, it means that no one in this "family" is related to anyone else (not good); 1 = everythings is fine; 2+= the family appears to be a set of disjoint trees. Are you missing some of the people?  | 
join | 
 number of other families that had a unique famid, but are actually joined to this one. 0 is the hope. If there are any joins, then an attribute "join" is attached. It will be a matrix with famid as row labels, new-family-id as the columns, and the number of subjects as entries.  | 
makefamid, makekinship
# use 2 sample peds
data(sample.ped)
pedAll <- with(sample.ped, pedigree(id, father, mother, sex,
                    affected=cbind(affected, avail), famid=ped))
## check them giving separate ped ids
fcheck.sep <- with(sample.ped, familycheck(ped, id, father, mother))
fcheck.sep
## check assigning them same ped id
fcheck.combined <- with(sample.ped, familycheck(rep(1,nrow(sample.ped)), id, father, mother))
fcheck.combined
#make person 120's father be her son.
sample.ped[20,3] <- 131
fcheck1.bad <- try({with(sample.ped, familycheck(ped, id, father, mother))}, silent=FALSE)
## fcheck1.bad is a try-error
Add the following code to your website.
For more information on customizing the embed code, read Embedding Snippets.