recode.haven_labelled | R Documentation |
Extend dplyr::recode()
method from dplyr to
works with labelled vectors.
## S3 method for class 'haven_labelled'
recode(
.x,
...,
.default = NULL,
.missing = NULL,
.keep_value_labels = TRUE,
.combine_value_labels = FALSE,
.sep = " / "
)
.x |
A vector to modify |
... |
< When named, the argument names should be the current values to be replaced, and the argument values should be the new (replacement) values. All replacements must be the same type, and must have either
length one or the same length as |
.default |
If supplied, all values not otherwise matched will
be given this value. If not supplied and if the replacements are
the same type as the original values in
|
.missing |
If supplied, any missing values in |
.keep_value_labels |
If TRUE, keep original value labels. If FALSE, remove value labels. |
.combine_value_labels |
If TRUE, will combine original value labels to generate new value labels. Note that unexpected results could be obtained if a same old value is recoded into several different new values. |
.sep |
Separator to be used when combining value labels. |
dplyr::recode()
x <- labelled(1:3, c(yes = 1, no = 2))
x
dplyr::recode(x, `3` = 2L)
# do not keep value labels
dplyr::recode(x, `3` = 2L, .keep_value_labels = FALSE)
# be careful, changes are not of the same type (here integers),
# NA arecreated
dplyr::recode(x, `3` = 2)
# except if you provide .default or new values for all old values
dplyr::recode(x, `1` = 1, `2` = 1, `3` = 2)
# if you change the type of the vector (here transformed into character)
# value labels are lost
dplyr::recode(x, `3` = "b", .default = "a")
# use .keep_value_labels = FALSE to avoid a warning
dplyr::recode(x, `3` = "b", .default = "a", .keep_value_labels = FALSE)
# combine value labels
x <- labelled(
1:4,
c(
"strongly agree" = 1,
"agree" = 2,
"disagree" = 3,
"strongly disagree" = 4
)
)
dplyr::recode(
x,
`1` = 1L,
`2` = 1L,
`3` = 2L,
`4` = 2L,
.combine_value_labels = TRUE
)
dplyr::recode(
x,
`2` = 1L,
`4` = 3L,
.combine_value_labels = TRUE
)
dplyr::recode(
x,
`2` = 1L,
`4` = 3L,
.combine_value_labels = TRUE,
.sep = " or "
)
dplyr::recode(
x,
`2` = 1L,
.default = 2L,
.combine_value_labels = TRUE
)
# example when combining some values without a label
y <- labelled(1:4, c("strongly agree" = 1))
dplyr::recode(y, `2` = 1L, `4` = 3L, .combine_value_labels = TRUE)
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