| partexp | R Documentation |
This function estimates the parameters of the Truncated Exponential distribution given
the L-moments of the data in an L-moment object such as that returned by lmoms. The parameter \psi is the right truncation of the distribution, and \alpha is a scale parameter, letting \beta = 1/\alpha to match nomenclature of Vogel and others (2008), and recalling the L-moments in terms of the parameters and letting \eta = \exp(-\beta\psi) are
\lambda_1 = \frac{1 - \eta + \eta\log(\eta)}{\beta(1-\eta)}\mbox{,}
\lambda_2 = \frac{1 + 2\eta\log(\eta) - \eta^2}{2\beta(1-\eta)^2}\mbox{, and}
\tau_2 = \frac{\lambda_2}{\lambda_1} = \frac{1 + 2\eta\log(\eta) - \eta^2}{2(1-\eta)[1-\eta+\eta\log(\eta)]}\mbox{,}
and \tau_2 is a monotonic function of \eta is decreasing from \tau_2 = 1/2 at \eta = 0 to \tau_2 = 1/3 at \eta = 1 the parameters are readily solved given \tau_2 = [1/3, 1/2], the R function uniroot can be used to solve for \eta with a starting interval of (0, 1), then the parameters in terms of the parameters are
\alpha = \frac{1 - \eta + \eta\log(\eta)}{(1 - \eta)\lambda_1}\mbox{, and}
\psi = -\log(\eta)/\alpha\mbox{.}
If the \eta is rooted as equaling zero, then it is assumed that \hat\tau_2 \equiv \tau_2 and the exponential distribution triggered, or if the \eta is rooted as equaling unity, then it is assumed that \hat\tau_2 \equiv \tau_2 and the uniform distribution triggered (see below).
The distribution is restricted to a narrow range of L-CV (\tau_2 = \lambda_2/\lambda_1). If \tau_2 = 1/3, the process represented is a stationary Poisson for which the probability density function is simply the uniform distribution and f(x) = 1/\psi. If \tau_2 = 1/2, then the distribution is represented as the usual exponential distribution with a location parameter of zero and a scale parameter 1/\beta. Both of these limiting conditions are supported.
If the distribution shows to be uniform (\tau_2 = 1/3), then the third element in the returned parameter vector is used as the \psi parameter for the uniform distribution, and the first and second elements are NA of the returned parameter vector.
If the distribution shows to be exponential (\tau_2 = 1/2), then the second element in the returned parameter vector is the inverse of the rate parameter for the exponential distribution, and the first element is NA and the third element is 0 (a numeric FALSE) of the returned parameter vector.
partexp(lmom, checklmom=TRUE, ...)
lmom |
An L-moment object created by |
checklmom |
Should the |
... |
Other arguments to pass. |
An R list is returned.
type |
The type of distribution: |
para |
The parameters of the distribution. |
ifail |
A logical value expressed in numeric form indicating the failure or success state of the parameter estimation. A value of two indicates that the |
ifail.message |
Various messages for successful and failed parameter estimations are reported. In particular, there are two conditions for which each distributional boundary (uniform or exponential) can be obtained. First, for the uniform distribution, one message would indicate if the |
eta |
The value for |
source |
The source of the parameters: “partexp”. |
W.H. Asquith
Vogel, R.M., Hosking, J.R.M., Elphick, C.S., Roberts, D.L., and Reed, J.M., 2008, Goodness of fit of probability distributions for sightings as species approach extinction: Bulletin of Mathematical Biology, DOI 10.1007/s11538-008-9377-3, 19 p.
lmomtexp, cdftexp, pdftexp, quatexp
# truncated exponential is a nonstationary poisson process
A <- partexp(vec2lmom(c(100, 1/2), lscale=FALSE)) # pure exponential
B <- partexp(vec2lmom(c(100, 0.499), lscale=FALSE)) # almost exponential
BB <- partexp(vec2lmom(c(100, 0.45), lscale=FALSE)) # truncated exponential
C <- partexp(vec2lmom(c(100, 1/3), lscale=FALSE)) # stationary poisson process
D <- partexp(vec2lmom(c(100, 40))) # truncated exponential
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