RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.1 is part of RBSE Solutions for Class 9 Maths. Here we have given Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Exercise 8.1.

Board |
RBSE |

Textbook |
SIERT, Rajasthan |

Class |
Class 9 |

Subject |
Maths |

Chapter |
Chapter 8 |

Chapter Name |
Construction of Triangles |

Exercise |
Ex 8.1 |

Number of Questions Solved |
6 |

Category |
RBSE Solutions |

## Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Ex 8.1

**Case I: To construct a triangle when all the three sides are given.**

Question 1.

Construct a triangle ABC where AB = 4 cm, BC = 5 cm and CA = 6 cm.

Solution.

Steps of construction:

- Draw BC = 5 cm.
- With B as centre, draw (RBSESolutions.com) an arc of radius 4cm

- With C as can be, draw arc of radius 6 cm Which cuts the former arc at A.
- Join AB and AC.
- Hence, ∆ABC is the required triangle.

Question 2.

Two points A and B are at a distance of 6.5 cm. Find (RBSESolutions.com) a point C at a distance of 7 cm from A and 6 cm from B.

Solution.

Steps of construction:

- Draw base AB = 6.5 cm.
- Take A and B as centre, draw arcs of radii 7 cm and 6 cm above the line and below the line which intersects at C and C’.

- Join AC, BC and C’A and C’B.
- Hence, ∆ABC and ∆ABC’ are the required triangles.

Question 3.

Construct a ∆ABC where a = 6.5 cm, b = 7.2 cm, c = 8 cm. Draw (RBSESolutions.com) the bisector of ∠B which meets AC at the point M.

Solution.

Steps of construction:

- Draw AC = 7.2 cm.
- By taking A as centre, draw an arc of radius 8 cm.
- Again take C as centre and draw an arc of radius 6.5 cm which cuts the previous arc at B.

- Join AB and AC. This gives the required ∆ABC.
- Now draw BM as bisector of ∠B which meets AC at M.

Question 4.

Construct a triangle ABC where a = l cm, b = 5 cm and c = 4 cm. Draw (RBSESolutions.com) perpendicular from A on BC.

Solution.

Steps of construction:

- Draw a = 7 cm.
- With centre B, draw an arc of radius 4 cm.

- With centre C, draw another arc of radius 5 cm which cuts the former arc at A.
- With centre A, draw ⊥ on BC i.e. AP.
- Join AB, AC and AP.

Hence, ∆ABC is the required triangle.

Question 5.

Construct an equilateral triangle (RBSESolutions.com) whose sides are of length 5.5 cm.

Solution.

Steps of construction:

- Draw BC = 5.5 cm.
- With B as centre, draw an arc of radius 5.5 cm.

- With C as centre, draw another arc of (RBSESolutions.com) radius 5.5 cm, which cuts the former arc at A.
- Join AB and AC.

Hence, ∆ABC is required equilateral triangle.

Question 6.

Construct an isosceles triangle whose base is of length 3 cm and the other sides are of 5 cm each.

Solution.

Steps of construction:

- Draw base BC = 3 cm.
- With centre B, draw an arc of radius 5 cm.

- With centre C, draw another arc of (RBSESolutions.com) radius 5 cm which cuts the former arc at A.
- Join BA and CA.

Hence, ∆ABC is the required isosceles triangle.

We hope the given RBSE Solutions for Class 9 Maths Chapter 8 Construction of Triangles Ex 8.1 will help you. If you have any query regarding Rajasthan Board RBSE Class 9 Maths Solutions Chapter 8 Construction of Triangles Exercise 8.1, drop a comment below and we will get back to you at the earliest.