R/time_exposed_outs.R In qlifetable: Managing and Building of Quarterly Life Tables

Documented in time_exposed_outs

#' Data frame of time exposed at risk for a population of deaths/emigrants/exits (portfolio withdrawals, lapses) during the year of the event.
#'
#' @description  Computes for each integer age and each combination of age and seasonal quarter
#'               the total time exposed at risk (in years) of a population of deceased/emigrants/exits
#'               (portfolio withdrawals, lapses) during the year of the event.
#'               The computation is performed using the associated data frame of quarterly variables
#'               corresponding to the population obtained using the \code{\link{quarterly_variables}} function.
#'
#' @author Josep Lledo \email{josep.lledo@@uv.es}
#' @author Jose M. Pavia \email{pavia@@uv.es}
#' @references Pavia, JM and Lledo, J (2022). Estimation of the Combined Effects of Ageing and Seasonality on Mortality Risk. An application to Spain. *Journal of the Royal Statistical Society, Series A (Statistics in Society)*, 185(2), 471-497. \doi{10.1111/rssa.12769}
#'
#' @param x A data.frame output of the \code{\link{quarterly_variables}} function.
#'
#' @return
#' A data frame with the time exposed at risk for each (potential) combination of integer age and age and
#' season quarter of the input dataset. The data frame has the following components:
#'    \item{age}{ Integer age to which the time exposed at risk corresponds.}
#'    \item{quarter.age}{ Age quarter to which the time exposed at risk corresponds.}
#'    \item{quarter.calendar}{ Calendar (time, season) quarter to which the time exposed at risk corresponds.}
#'    \item{time.exposed}{ Total time (in years) exposed at risk of the population during the quarter determined for the
#'                         combination of age, quarter.age and quarter.calendar.}
#'
#' @note
#' The time exposed at risk is computed for each person from the beginning of the year in which the event occurred
#' until the moment of occurrence of the event. Please see the note in the \code{\link{time_exposed_stock}} function.
#'
#'
#' @export
#'
#' @examples
#' dates.b <- c("1920-05-13", "1999-04-12", "2019-01-01")
#' dates.e <- c("2002-03-23", "2009-04-12", "2019-01-01")
#' x <- quarterly_variables(dates.b, dates.e)
#' out <- time_exposed_outs(x)

time_exposed_outs <- function(x){

#  x$triangle <- ifelse((4 * x$coord.age)%%1 > (4 * x$coord.time)%%1, "upp", "low" ) x$triangle <- ifelse (x$coord.age - 0.25 * (x$quarter.age - 1L) > x$coord.time - 0.25 * (x$quarter.calendar - 1L), "upp", "low" )

max.age <- max(floor(x$age.last.birthday)) table <- data.frame(matrix(0L, ncol = 4L, nrow = (max.age + 1L) * 4L * 4L)) colnames(table) <- cbind("age", "quarter.age", "quarter.calendar", "time.exposed") table$age <- rep(0L:max.age, each = 16L)
table$quarter.age <- rep(rep(1L:4L, each = 4L), max.age + 1L ) table$quarter.calendar <- rep(1L:4L, length.out = (max.age + 1L) * 4L * 4L)

for (k in 0L:max.age){

# Seleccionamos de la df la edad a estudiar
df.sel <- x[x$age.last.birthday == k, ] if(nrow(df.sel) != 0L){ for (age.0 in 1L:4L){ for (season.0 in 1L:4L){ # Asignamos un ID key.df.x.out <- key_assignment_x_out(df.sel$quarter.age,
df.sel$quarter.calendar, df.sel$triangle,
age.0,
season.0)
key.df.x.out <- cbind.data.frame("coord.time" = df.sel$coord.time, "coord.age" = df.sel$coord.age,
key.df.x.out)

key.df.x.1.out <- key_assignment_x_1_out(df.sel$quarter.age, df.sel$quarter.calendar,
df.sel$triangle, age.0, season.0) key.df.x.1.out <- cbind.data.frame("coord.time" = df.sel$coord.time,
"coord.age" = df.sel$coord.age, key.df.x.1.out) key.df.x.out <- key.df.x.out[!is.na(key.df.x.out$key), ]
key.df.x.1.out <- key.df.x.1.out[!is.na(key.df.x.1.out$key), ] # Calculamos el tiempo de exposicion al riesgo time.x <- time_exposed_x_out(key.df.x.out$coord.time,
key.df.x.out$coord.age, key.df.x.out$key)
time.x.1 <- time_exposed_x_1_out(key.df.x.1.out$coord.time, key.df.x.1.out$coord.age,
key.df.x.1.out$key) # Sumamos todo el tiempo de exposicion al riesgo t.time.x <- sum(time.x, na.rm = TRUE) t.time.x.1 <- sum(time.x.1, na.rm = TRUE) # Guardar datos table$time.exposed[k * 16L + (age.0 - 1L) * 4L + season.0] <- table$time.exposed[k * 16L + (age.0 - 1L) * 4L + season.0] + t.time.x if (k != 0L) table$time.exposed[(k - 1L) * 16L + (age.0 - 1L) * 4L + season.0] <- table\$time.exposed[(k - 1L) * 16L + (age.0 - 1L) * 4L + season.0] + t.time.x.1
} # Next age.0
} # Next season.0
} # End if nrow
} # Next k

table <- methods::new("qlifetable", table)
return(table)

}

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qlifetable documentation built on Sept. 29, 2022, 9:06 a.m.