parse_factor | R Documentation |
parse_factor()
is similar to factor()
, but generates a warning if
levels
have been specified and some elements of x
are not found in those
levels
.
parse_factor( x, levels = NULL, ordered = FALSE, na = c("", "NA"), locale = default_locale(), include_na = TRUE, trim_ws = TRUE ) col_factor(levels = NULL, ordered = FALSE, include_na = FALSE)
x |
Character vector of values to parse. |
levels |
Character vector of the allowed levels. When |
ordered |
Is it an ordered factor? |
na |
Character vector of strings to interpret as missing values. Set this
option to |
locale |
The locale controls defaults that vary from place to place.
The default locale is US-centric (like R), but you can use
|
include_na |
If |
trim_ws |
Should leading and trailing whitespace (ASCII spaces and tabs) be trimmed from each field before parsing it? |
Other parsers:
col_skip()
,
cols_condense()
,
cols()
,
parse_datetime()
,
parse_guess()
,
parse_logical()
,
parse_number()
,
parse_vector()
# discover the levels from the data parse_factor(c("a", "b")) parse_factor(c("a", "b", "-99")) parse_factor(c("a", "b", "-99"), na = c("", "NA", "-99")) parse_factor(c("a", "b", "-99"), na = c("", "NA", "-99"), include_na = FALSE) # provide the levels explicitly parse_factor(c("a", "b"), levels = letters[1:5]) x <- c("cat", "dog", "caw") animals <- c("cat", "dog", "cow") # base::factor() silently converts elements that do not match any levels to # NA factor(x, levels = animals) # parse_factor() generates same factor as base::factor() but throws a warning # and reports problems parse_factor(x, levels = animals)
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