bcoov: Calculate Bray-Curtis distance for only one variable
In simba: A Collection of functions for similarity analysis of vegetation data

Description Usage Arguments Details Value Author(s) See Also Examples

Calculates Bray-Curtis distance for only one variable: How dissimilar are the units regarding for instance pH?

1	bcoov(x, names, listout = FALSE)

`x`	numeric vector with quantitative data from sampling-units, standardization may be applied before
`names`	where should the names be taken from, must be a vector of the same length as `x` and should give the names of the sampling-units
`listout`	Shall the result given in list-format (`data.frame`)? Defaults to FALSE

It is just a simple way to calculate similarity based on only one variable. In the future there might be a possibility to choose from some functions. However, you could also use the difference in the data-values instead (which is the Euclidean distance in one dimensional space).

Returns a dist object or a data.frame (in the case of listout = TRUE) with

`NBX`	one of the compared sampling units
`NBY`	the other part of the pair
`x`	The returned distance value. It is named like the tested variable

Gerald Jurasinski

vegdist, dist.quant, dsvdis

data(abis)
names(abis.env) ##take a look at the data
##calculate the similarity (Bray-Curtis) between the plots 
##regarding pH
pH.dist <- bcoov(abis.env$pH, names=rownames(abis.env))

## directly give it as a list (data.frame)
pH.dist.ls <- bcoov(abis.env$pH, names=rownames(abis.env)
, listout=TRUE)