named_contr_sum: Create named sum contrasts for an unordered factor.
In standardize: Tools for Standardizing Variables for Regression in R

Description Usage Arguments Details Value Author(s) See Also Examples

named_contr_sum creates sum contrasts for a factor which are named with the levels of the factor rather than with numbers (e.g. if a factor f1 has levels A, B, and C, then rather than creating contrast columns f11 and f12, it creates columns f1A and f1B). The absolute value of the non-zero elements of the matrix can also be specified.

1	named_contr_sum(x, scale = 1, return_contr = TRUE)

`x`	An object coercible to factor or a numeric or character vector of levels.
`scale`	A positive number by which the entire contrast matrix returned by `contr.sum` is multiplied. See 'Details'.
`return_contr`	A logical. If `TRUE` (the default), a contrast matrix is returned. If `FALSE`, `x` is converted to an unordered factor with the contrast matrix applied, and the factor is returned.

First, x is coerced to factor, and its levels (excluding NA) are sorted alphabetically. If there are two unique values, and they are equal to (ignoring case) "F" and "T", "FALSE" and "TRUE", "N" and "Y", "NO" and "YES", or "0" and "1", then their order is reversed (this makes it so the positive level gets the dummy coefficient rather than the negative level, yielding a more intuitive interpretation for coefficients). Then contr.sum is called, and the column names of the resulting contrast matrix are set using the character vector of unique values (excluding the final element that gets coded as -1 for all dummy variables). This entire matrix is then multiplied by scale; with the default value of 1, this does not change the matrix; if, for example, scale = 0.5, then rather than each column containing values in -1, 0, 1, each column would contain values in -0.5, 0, 0.5. If return_contr = TRUE, then this contrast matrix is returned. If return_contr = FALSE, then x is converted to an unordered factor with the named sum contrasts and returned. NA is never assigned as a level in the contrast matrix or in the factor returned by the function, but NA values in x are not removed in the factor returned when return_contr = FALSE. See the examples.

If return_contr = TRUE, a contrast matrix obtained from contr.sum with named columns rather than numbered columns and deviations with magnitude scale. If return_contr = FALSE, then x is returned as an unordered factor with the named sum contrasts applied.

Christopher D. Eager <eager.stats@gmail.com>

scaled_contr_poly for ordered factors.

f <- factor(rep(c("a", "b", "c", NA), 2), levels = c("b", "c", "a"))
f <- addNA(f)
levels(f)  # NA listed as factor level
contrasts(f)  # NA included in contrast matrix
named_contr_sum(f)  # named sum contrasts (NA dropped; levels alphabetized)
named_contr_sum(levels(f))  # same output
named_contr_sum(f, return_contr = FALSE)  # factor with named sum contrasts
named_contr_sum(f, 0.5)  # deviations of magniude 0.5

f <- c(TRUE, FALSE, FALSE, TRUE)
class(f)  # logical
named_contr_sum(f)  # TRUE gets the dummy variable
f <- named_contr_sum(f, return_contr = FALSE)
class(f)  # factor

named_contr_sum(letters[1:5])  # character argument
named_contr_sum(rep(letters[1:5], 2), return_contr = FALSE)  # creates factor

# ordered factors are converted to unordered factors, so use with caution
f <- factor(rep(1:3, 2), ordered = TRUE)
is.ordered(f)  # TRUE
f
f <- named_contr_sum(f, return_contr = FALSE)
is.ordered(f)  # FALSE
f

## Not run: 
# error from stats::contr.sum because only one unique non-NA value
named_contr_sum(5)
named_contr_sum(rep(c("a", NA), 3))

## End(Not run)