KaplanMeier | R Documentation |
Computes the Kaplan-Meier estimator to estimate a risk or, equivalently, a survival probability, with right-censored data, together with a confidence interval and (possibly) a p-value (for a one-sample hypothesis test). Computation of confidence intervals and p-values is based on either Empirical Likelihood (EL) inference or Wald-type inference. Both are non-parametric approaches, which are asymptotically equivalent. See Thomas & Grunkemeier (1975) for details about the Empirical Likelihood method. For the Wald-type approach, the asymptotic normal approximation is used on the cloglog scale. See e.g. equation 4.16 in Beyersmann et al (2011).
KaplanMeier(
time,
status,
t,
risk.H0 = NULL,
level = 0.95,
contr = list(tol = 1e-05, k = 3, Trace = FALSE, method = "both")
)
time |
vector of times (possibly censored) |
status |
vector of usual survival status indicators (0 for censored observations, 1 for events) |
t |
the time point of interest (e.g. 1 to compute a 1-year risk or survival probability) |
risk.H0 |
risk under the null hypothesis, if one would like to compute the correspondng p-value. Default is NULL, for which no p-value is computed. |
level |
confidence level for the confidence intervals. Default is 0.95. |
contr |
list of control parameters. tol=tolerance for numerical computation, default is 1e-5. method="EL", "Wald" or "both" indicates wether 95% CI and p-value should be computed based on Empirical Likelihood (EL) inference , Wald-type inference or both. |
object of class 'KaplanMeier'
Paul Blanche
Thomas & Grunkemeier (1975). Confidence interval estimation of survival probabilities for censored data. Journal of the American Statistical Association, 70(352), 865-871.
Beyersmann, Allignol, & Schumacher (2011). Competing risks and multistate models with R. Springer Science & Business Media.
# This example reproduces some results presented in Table 1 of Thomas and Grunkemeier (1975)
ResKM.1.95 <- KaplanMeier(time=Freireich$time[Freireich$group==1],
status=Freireich$status[Freireich$group==1],
t=10, level=0.95, contr=list(tol=1e-4))
ResKM.1.95
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